Question

我有像这样的javascript基本功能;

roomBase = function () {
  this.go = function(){
    alert(1);
  }
}

我有这样的房间对象;

myRoom = function(){
  this.go = function(){
    alert(456);
  }
}
myRoom.prototype = new roomBase();
theRoom = new myRoom();

当我致电theRoom.go()时，我收到来自prototype的提醒。我想要的是来自myRoom功能的警报。

Answer 1

对我来说很好。（它警告456）

您确定一切正常吗？

演示：http://jsfiddle.net/9hWAr/

演示代码：

var roomBase = function () {
  this.go = function(){
    alert(1);
  }
}

var myRoom = function(){
  this.go = function(){
    alert(456);
  }
}
myRoom.prototype = new roomBase();
var theRoom = new myRoom();

theRoom.go()

覆盖原型方法

1 个答案: