如果你足够快地点击顶部的div,你会发现最终会出现两个div。我之前也遇到过jQuery这个问题。在这种情况下,我刚刚结束禁用按钮(或动画触发器),但我想知道是否有更优雅的解决方案。
这是我的jQuery代码 -
$(function () {
var _animDuration = 400;
$("#tabLists a").click(function () {
var attrHref = $(this).attr('href');
// Get shown anchor and remove that class -
$('.shownAnchor').removeClass('shownAnchor');
$(this).addClass('shownAnchor');
// first hide currently shown div,
$('.shownDiv').fadeOut(_animDuration, function () {
debugger;
// then remove the shownDiv class, show the clicked div.
$(this).removeClass('shownDiv');
$('#' + attrHref).fadeIn(_animDuration, function () {
// then add that shownDiv class to the div currently being shown.
$(this).addClass('shownDiv');
})
});
return false;
});
});
我到处都在使用回调。我想要一个排队动画的解决方案,而不是让我点击
答案 0 :(得分:0)
使用check var:
尝试此代码$(function(){
var check = 1;
var _animDuration = 400;
$("#tabLists a").click(function(){
if(check == 1){
check = 0;
var attrHref = $(this).attr('href');
// Get shown anchor and remove that class -
$('.shownAnchor').removeClass('shownAnchor');
$(this).addClass('shownAnchor');
// first hide currently shown div,
$('.shownDiv').fadeOut(_animDuration, function(){
debugger;
// then remove the shownDiv class, show the clicked div.
$(this).removeClass('shownDiv');
$('#' + attrHref).fadeIn(_animDuration, function(){
// then add that shownDiv class to the div currently being shown.
$(this).addClass('shownDiv');
check = 1;
})
});
}
return false;
});
});