我有一个问题。所以我发现你可以用HTML上传图像,我使用了以下代码:
<form name="imageUpload" method="post">
<input type="file" multiple accept = image/* name="uploadField"/>
</form>
然而,鉴于使用AngularJS,我想知道是否有办法在上传图像时在屏幕上的另一个位置显示图像。如果有人可以指出我在正确的方向,那将是伟大的!谢谢!
答案 0 :(得分:8)
这是更多的JavaScript问题。正如在这里所回答的this answer。角度应该是这样的:
<!doctype html>
<html lang="en">
<head >
<meta charset="UTF-8">
<title>Upload Image</title>
<script type="text/javascript" src="angular.min.js"></script>
<script type="text/javascript">
angular.module('myApp', []).
controller('UploadCtrl', ['$scope', function (scope) {
scope.image = "";
}]).
directive('myUpload', [function () {
return {
restrict: 'A',
link: function (scope, elem, attrs) {
var reader = new FileReader();
reader.onload = function (e) {
scope.image = e.target.result;
scope.$apply();
}
elem.on('change', function() {
reader.readAsDataURL(elem[0].files[0]);
});
}
};
}]);
</script>
</head>
<body ng-app="myApp">
<div ng-controller="UploadCtrl">
<img ng-if="image" src="{{image}}" alt="">
<form action="">
<input my-upload type="file" name="upload">
</form>
</div>
</body>
</html>
答案 1 :(得分:-1)
你可以像我一样做一些事情:Plunker
<!DOCTYPE html>
<html ng-app="app">
<head>
<link data-require="bootstrap-css@*" data-semver="3.0.2" rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.0.2/css/bootstrap.min.css" />
<script data-require="angular.js@1.2.0" data-semver="1.2.0" src="http://code.angularjs.org/1.2.0/angular.js"></script>
<link rel="stylesheet" href="style.css" />
<script type="text/javascript" src="script.js"></script>
</head>
<body ng-controller="MainCtrl" >
<canvas image-display file-data="{{data}},{{mimeType}},{{fileName}}"></canvas>
</body>
</html>