我在创建用户时使用Django创建用户和对象。但是有一个错误
__init__() got an unexpected keyword argument 'user'
在view.py中调用register()
函数时。
功能是:
def register(request):
'''signup view'''
if request.method=="POST":
form=RegisterForm(request.POST)
if form.is_valid():
username=form.cleaned_data["username"]
email=form.cleaned_data["email"]
password=form.cleaned_data["password"]
user=User.objects.create_user(username, email, password)
user.save()
return HttpResponseRedirect('/keenhome/accounts/login/')
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
#This is used for reinputting if failed to register
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
,对象类是:
class LivingRoom(models.Model):
'''Living Room object'''
user = models.OneToOneField(User)
def __init__(self, temp=65):
self.temp=temp
TURN_ON_OFF = (
('ON', 'On'),
('OFF', 'Off'),
)
TEMP = (
('HIGH', 'High'),
('MEDIUM', 'Medium'),
('LOW', 'Low'),
)
on_off = models.CharField(max_length=2, choices=TURN_ON_OFF)
temp = models.CharField(max_length=2, choices=TEMP)
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
LivingRoom.objects.create(user=instance)
post_save.connect(create_control_livingroom, sender=User)
Django错误页面通知错误信息:
user=User.objects.create_user(username, email, password)
和
LivingRoom.objects.create(user=instance)
我试图搜索这个问题,找到一些案例,但仍然无法弄清楚如何解决它。
答案 0 :(得分:9)
你做不到
LivingRoom.objects.create(user=instance)
因为你有一个不以user
为参数的init方法。
你想要像
这样的东西#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
my_room = LivingRoom()
my_room.user = instance
答案 1 :(得分:7)
我得到了同样的错误。
在我的观点中,我像这样覆盖了get_form_kwargs():
class UserAccountView(FormView):
form_class = UserAccountForm
success_url = '/'
template_name = 'user_account/user-account.html'
def get_form_kwargs(self):
kwargs = super(UserAccountView, self).get_form_kwargs()
kwargs.update({'user': self.request.user})
return kwargs
但在我的表单上,我未能覆盖 init ()方法。一旦我做到了。问题解决了
class UserAccountForm(forms.Form):
first_name = forms.CharField(label='Your first name', max_length=30)
last_name = forms.CharField(label='Your last name', max_length=30)
email = forms.EmailField(max_length=75)
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(UserAccountForm, self).__init__(*args, **kwargs)
答案 2 :(得分:2)
LivingRoom.objects.create()
调用LivingRoom.__init__()
- 您可能已经注意到,如果您已经阅读了回溯 - 将相同的参数传递给它。总而言之,Django models.Model
子类的初始化器最好不要单独使用,或者接受* args和** kwargs匹配模型的元字段。为字段提供默认值的正确方法是使用default
关键字在字段构造函数中,如FineManual中所述。
答案 3 :(得分:0)
检查您的进口。可能有两个同名的类。从您的代码或正在使用的库中。就个人而言,这就是问题所在。