Question

我花了几个小时阅读并试图弄清楚为什么这不起作用但是下拉菜单没有填充。我认为这很简单，但我看不到它。任何人吗？

dbconn.php

<?php

define('DB_NAME' , 'artprints');
define('DB_USER' , 'root');
define('DB_PASS' , '');
define('DB_HOST' , 'localhost');

func.php

<?php

include_once 'dbconn.php';

function connect(){
    $connection = mysqli_connect(DB_HOST, DB_USER, DB_PASS) or die ('Could not connect to the database' . mysl_error());
    mysqli_select_db($connection, DB_NAME);
}

function close(){
    mysql_close();
}

function query(){
    $myData = mysql_query("SELECT * FROM artists");
    while ($record = mysql_fetch_array($myData)){
    echo '<option value="' . $record['artistID'] . '">' . $record['artistID'] . '</option>';
    }
}

test.php的

<?php
 include_once 'func.php';
 connect();
 ?>

 <html>
 <head>
 <title>Drop down testing</title>
 </head>
 <body>
 <select name='artist'>
 <?php query() ?>
 </select>
 <?php close() ?>
 </body>
 </html>

Answer 1

您正在混合mysqli_*和mysql_*

mysqli_connect和mysqli_select_db

针对

mysql_query和mysql_fetch_array

Answer 2

将其复制并粘贴到您的function.php

中

include_once ('dbconn.php');

function connect()
{
    $connection = mysqli_connect(DB_HOST, DB_USER, DB_PASS) or die ('Could not connect to the database' . mysl_error());
    mysqli_select_db($connection, DB_NAME);
}

function close(){
    mysqli_close();
}

function query(){
    $myData = mysqli_query("SELECT * FROM artists");
    while ($record = mysql_fetch_array($myData)){
    echo '<option value="' . $record['artistID'] . '">' . $record['artistID'] . '</option>';
    }
}

从mysql填充的PHP下拉菜单不起作用

2 个答案: