我有一个Web服务器,它收到很多关于同一主题的消息,并将响应消息返回给另一个主题。
我目前正在通过保持MQTT客户端始终连接来重新使用相同的MQTT客户端实例进行回调和发送响应消息。
但是,在收到消息并发送响应的一个周期后,我能够收到另一条消息但无法发送响应 - 我必须重新启动应用程序服务器。
拥有单个MQTTclient实例是一种好方法吗?可以一直保持连接吗?这种要求的最佳方法是什么?
这是我的代码:
public static void registerCallBack(String topicName, String userName,
String password, String clientId, MqttCallback callback,
MqttClient client) {
MqttConnectOptions options = new MqttConnectOptions();
options.setCleanSession(true);
options.setKeepAliveInterval(30);
options.setUserName(userName);
options.setPassword(password.toCharArray());
// Connect to Broker
try {
options.setSocketFactory(SslUtil.getSocketFactory(
ManagerProps.MQTT_BROKER_CA_FILE.getValue(), ""));
client.setCallback(callback);
client.connect(options);
client.subscribe(topicName, 0);
log.info("successfuly registered callback to topic " + topicName);
} catch (MqttException me) {
log.error("MqttException, " + me);
} catch (Exception e) {
log.error("Exception, " + e);
}
}
public static String publishMessage(MqttClient client, String message,
String topic, String userName, String password) {
MqttConnectOptions options = new MqttConnectOptions();
options.setCleanSession(true);
options.setKeepAliveInterval(30);
options.setUserName(userName);
options.setPassword(password.toCharArray());
try {
MqttMessage msg = new MqttMessage();
msg.setPayload(message.getBytes());
client.publish(topic, msg);
} catch (MqttException e) {
log.error("MqttException, " + e);
} catch (Exception e) {
log.error("Exception, " + e);
}
return message;
}
答案 0 :(得分:0)
我看到类似的东西,并让它工作:
final CallbackConnection connection = mqtt.callbackConnection();
connection.listener(new org.fusesource.mqtt.client.Listener() {
public void onConnected() {
}
public void onDisconnected() {
}
public void onFailure(Throwable value) {
value.printStackTrace();
System.exit(-2);
}
public void onPublish(UTF8Buffer topic, Buffer msg, Runnable ack) {
String body = msg.utf8().toString();
if( body.startsWith("REPLY: ")) {
// Don't reply to your own reply
System.out.println("Replied");
System.out.println("");
} else {
try{
byte[] reply = "REPLY: Hello Back".getBytes();
connection.publish(destination, reply, QoS.AT_MOST_ONCE, true, null) ;
msg.clear();
}catch (Exception e){
e.printStackTrace();
}
}
}
});