Question

Get["/"] = _ =>"some data";
Post["/"] = _ =>new {detail="detail.."};

我需要将响应转换为此格式

{
   state: state code
   data: origin data
}

所以，我添加了一个后挂钩

After.AddItemToEndOfPipeline(ResponseFormatHook);
...
private void ResponseFormatHook(NancyContext ctx)
{
    var apiResponse = new APIResponse();
    apiResponse.State = ctx.Response.StatusCode;

    using(var stream = new MemoryStream())
    {
        ctx.Response.Contents.Invoke(stream);
        stream.Position = 0;
        using (var reader = new StreamReader(stream))
        {
            // get the origin data
            var content = reader.ReadToEnd();
            apiResponse.Data = content;
        }
    }

    var response = new JsonResponse(apiResponse, new DefaultJsonSerializer());
    response.StatusCode = HttpStatusCode.OK;

    ctx.Response = response;
}

Get["/"]，没关系。将返回{state:200,data:"some data"}。

但对于Post["/"]，将返回{state:200,data:"{detail:\"detail..\"}"}。数据转换为字符串而非对象。客户端无法立即反序列化。

那么，我怎样才能获得原始数据？

apiResponse.Data=OriginData，这没关系。

编辑1

也许我可以将数据反序列化为

apiResponse.Data=JsonConvert.Deserialize(apiResponse.Data)。

但我觉得这个花费太多了，不是吗？

Answer 1

使用IResponseProcessor将触摸原始数据。

public class APIResponseProcessor : IResponseProcessor
{
    private static readonly IEnumerable<Tuple<string, MediaRange>> extensionMappings =
        new[] {new Tuple<string, MediaRange>("json", MediaRange.FromString("application/json"))};

    public ProcessorMatch CanProcess(MediaRange requestedMediaRange, dynamic model, NancyContext context)
    {
        var match = new ProcessorMatch();
        match.ModelResult = MatchResult.DontCare;
        match.RequestedContentTypeResult = MatchResult.ExactMatch;

        return match;
    }

    public Response Process(MediaRange requestedMediaRange, dynamic model, NancyContext context)
    {
        var apiResponse = new APIResponse();
        apiResponse.Data = model;

        return new JsonResponse(apiResponse,new DefaultJsonSerializer());
    }

    public IEnumerable<Tuple<string, MediaRange>> ExtensionMappings { get { return extensionMappings; } }
}

使用处理器代替After hook。

如何获取原点返回的对象

1 个答案: