只需查看SpringMVC-3.2.x
控制器操作方法的代码段即可。生成JSON
非常容易,但无法为特定控制器的此操作/特定操作方法添加addtional自定义标头。并非适用于所有JSON
@ResponseBody
操作方法。
@RequestMapping(value="ajaxDenied", method = RequestMethod.GET)
public @ResponseBody Map<String, Object> ajaxDenied(ModelMap model) {
Map<String, Object> message = new HashMap<String, Object>();
message.put("severity", "error");
message.put("summary", "Restricted access only");
message.put("code", 200);
Map<String, Object> json = new HashMap<String, Object>();
json.put("success", false);
json.put("message", message);
return json;
}
以不同的方式,我可以添加额外的标头作为我的需求,但这是生成纯JSON
的一些问题。它生成了错误JSON
并且能够解析几个浏览器。
@RequestMapping(value="ajaxSuccess", method = RequestMethod.GET)
public ResponseEntity<String> ajaxSuccess(){
Map<String, Object> message = new HashMap<String, Object>();
message.put("severity", "info");
message.put("location", "/");
message.put("summary", "Authenticated successfully.");
message.put("code", 200);
Map<String, Object> json = new HashMap<String, Object>();
json.put("success", true);
json.put("message", message);
String data = "";
try {
ObjectMapper mapper = new ObjectMapper();
data = mapper.writeValueAsString(json);
} catch (Exception e) { //TODO
}
HttpHeaders headers = new HttpHeaders();
headers.add("Content-Type", "application/json; charset=UTF-8");
headers.add("X-Fsl-Location", "/");
headers.add("X-Fsl-Response-Code", "302");
return (new ResponseEntity<String>(data, headers, HttpStatus.OK));
}
这个动作方法可以生成带有转义字符而不是纯JSON
的{{1}}字符串,因此依赖于浏览器将如何解析它,导致chrome失败。输出看起来像
JSON
但是我们想要的输出
"{\"message\":{\"summary\":\"Authenticated successfully.\",\"location\":\"/\",\"severity\":\"info\",\"code\":\"200\"},\"success\":true}"
我想根据特定控制器的特定操作条件生成带有额外标头的纯{
"message":{
"summary": "Authenticated successfully.",
"location":"/",
"severity":"info",
"code":"200"
},
"success":true
}
。
答案 0 :(得分:27)
您可以向ResponseEntity构建器添加标头。我认为这样更干净。
import org.springframework.http.HttpHeaders;
import org.springframework.http.ResponseEntity;
// ...
@GetMapping("/my/endpoint")
public ResponseEntity myEndpointMethod() {
HttpHeaders headers = new HttpHeaders();
headers.add(HttpHeaders.CONTENT_TYPE, "application/json; charset=UTF-8");
return ResponseEntity.ok()
.headers(headers)
.body(data);
}
答案 1 :(得分:16)
这是解决方案,作为 M的建议。 Deinum
@RequestMapping(value="ajaxSuccess", method = RequestMethod.GET)
public ResponseEntity<Map<String, Object>> ajaxSuccess(){
Map<String, Object> message = new HashMap<String, Object>();
message.put("severity", "info");
message.put("location", "/");
message.put("summary", "Authenticated successfully.");
message.put("code", 200);
Map<String, Object> json = new HashMap<String, Object>();
json.put("success", true);
json.put("message", message);
HttpHeaders headers = new HttpHeaders();
headers.add("Content-Type", "application/json; charset=UTF-8");
headers.add("X-Fsl-Location", "/");
headers.add("X-Fsl-Response-Code", "302");
return (new ResponseEntity<Map<String, Object>>(json, headers, HttpStatus.OK));
}
答案 2 :(得分:6)
您还可以使用HttpServletResponse
以更简单的方式添加状态和标题:
@RequestMapping(value="ajaxSuccess", method = RequestMethod.GET)
@ResponseBody
public String ajaxSuccess(HttpServletResponse response) {
response.addHeader("header-name", "value");
response.setStatus(200);
return "Body";
}
因此,您需要添加以下maven依赖提供:
<dependency>
<groupId>org.apache.tomcat</groupId>
<artifactId>tomcat-servlet-api</artifactId>
<version>7.0.53</version>
<scope>provided</scope>
</dependency>