Question

我对谷歌图表有疑问，当我使用addRows命令时，我的php变量是否足以满足所需的格式？

我会把我正在使用的代码放在：

<!--Load the AJAX API-->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">

        google.load("visualization", "1.0",{"packages":["corechart"]});

        google.setOnLoadCallback(drawChart);

        function drawChart(){
            //create the data table
            var data = new google.visualization.DataTable();
            data.addColumn("string","Fruits");
            data.addColumn("number","Amount");
            data.addRows([<?php echo "'$jsRows'";?>]);

            //set chart options
            var options = {"title":"Amount of different fruits",
                "width":400,
                "height":300};

            //instantiate and draw chart, passing in options
            var options = new google.visualization.PieChart(document.getElementById("chart_div"));
            chart.draw(data, options);
            } //end of drawchart function
            </script>

我写的时候：echo $jsRows;我得到：["0 as 6 h",0],["6 as 12h",0],["12 as 18h",8],["18 as 24h",0]，这是谷歌图表可以处理的数据格式，但是使用此代码，我的图表不会出现。有谁知道为什么？提前谢谢！

Answer 1

您应该从$jsRows变量周围删除引号。使用引号将数组转换为字符串，这与#addRows方法不兼容。这样做：

data.addRows([<?php echo $jsRows;?>]);

Google Charts - 使用谷歌图表绘制现有的PHP数组

1 个答案: