在计算2个不同的unix时间戳之间的差异后,我一直无法显示小时和分钟。假设我有这两个unix时间戳:
1) 1384327800
2) 1384300800
差异是
27000
如果我除了27000/3600我得
7.5
但我想要的是显示
7:30
或
7 hours and 30 minutes
最好的方法是什么?
答案 0 :(得分:4)
所有你需要做一点计算:
$diff = 27000;
$hour = floor($diff / 3600);
$min = floor(($diff - $hour * 3600) / 60);
$sec = $diff - $hour * 3600 - $min * 60;
echo "$hour hours, $min minutes, $sec seconds";
或者尝试使用DateTime类:
$dt1 = new DateTime('@1384327800');
$dt2 = new DateTime('@1384300801');
$diff = $dt1->diff($dt2);
echo $diff->format('%h hours, %i minutes, %s seconds');
答案 1 :(得分:3)
算法方式(不使用任何函数/库自动计算):
$diff_in_minutes = ($timestamp1 - $timestamp2) / 60;
$minutes = $diff_in_minutes % 60;
$hours = ($diff_in_minutes - $minutes) / 60;
$diff_string = $hours . ':' . $minutes;
答案 2 :(得分:2)
查看DateTime()
和DateInterval::format()
$dt1 = new DateTime('@1384327800');
$dt2 = new DateTime('@1384300800');
$diff = $dt1->diff($dt2);
echo $diff->format('%h hours and %i minutes');
如果需要,最后一点可以从字符串中删除不必要的时间段。
$elapsed = $diff->format('%y years, %m months, %a days, %h hours, %i minutes, %S seconds');
$elapsed = str_replace(array('0 years,', ' 0 months,', ' 0 days,', ' 0 hours,', ' 0 minutes,'), '', $elapsed);
$elapsed = str_replace(array('1 years, ', ' 1 months, ', ' 1 days, ', ' 1 hours, ', ' 1 minutes'), array('1 year, ', '1 month, ', ' 1 day, ', ' 1 hour, ', ' 1 minute'), $elapsed);
echo $elapsed;
答案 3 :(得分:1)
完全按照描述进行完整的长格式化:
date_default_timezone_set('UTC');
$timestamp1 = new DateTime('@1384327800');
$timestamp2 = new DateTime('@1384300800');
$diff = $timestamp1->diff($timestamp2);
$timemap = array('y' => 'year',
'm' => 'month',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
's' => 'second');
$timefmt = array();
foreach ($timemap as $prop => $desc) {
if ($diff->$prop > 0) {
$timefmt[] = ($diff->$prop > 1) ? "{$diff->$prop} {$desc}s" : "{$diff->$prop} $desc";
}
}
$diffstr = (count($timefmt) > 1)
? $diff->format(sprintf('%s and %s',
implode(', ', array_slice($timefmt, 0, -1)), end($timefmt)))
: end($timefmt);
var_dump($diffstr);
这给了我以下内容:
string(22) "7 hours and 30 minutes"