Question

正如标题所示，我正在尝试使用C＃在Unity中生成过程十六进制网格。

void Start () 
{
    //5 mid
     startRowSize = 5;

    for (int i = 0; i < startRowSize; i++)
    {
        GameObject newHex = (GameObject)Instantiate(hex);
        hexWidth = newHex.gameObject.renderer.bounds.size.z;
        newHex.transform.Rotate(new Vector3(0,30,0));
        newHex.transform.position = new Vector3((i * hexWidth),0,0);
    }

    for (int row = 0; row <= startRowSize-1; row ++)
    {
    for (int i = 0; i < row; i++)
    {
        GameObject newHex = (GameObject)Instantiate(hex);
        newHex.transform.Rotate(new Vector3(0,30,0));
        newHex.transform.position = new Vector3(((i*hexWidth)+((hexWidth/2))+(row*(hexWidth/2))),0,((startRowSize-row))*-(hexWidth/1.17f));
    }
    }
}

代码有效，但行是“向后”生成的，这意味着外部行包含更多的hexes，而内部行包含最小的行。

这显然是我想要实现的相反效果。几个小时我一直在搞乱这段代码，我无法弄清楚原因。

有什么想法吗？

Answer 1

因此，经过几个小时的代码处理后，我弄清楚为什么它没有正确迭代。他是精致的代码......

void Start () 
{
    //5 mid
     startRowSize = 10;

    for (int i = 0; i < startRowSize; i++)
    {
        GameObject newHex = (GameObject)Instantiate(hex);
        hexWidth = newHex.gameObject.renderer.bounds.size.z;
        newHex.transform.Rotate(new Vector3(0,30,0));
        newHex.transform.position = new Vector3((i * hexWidth),0,0);
    }

    for (int row = 0; row < startRowSize; row++)
    {
        for (int i = 0; i < startRowSize-1-row; i++)
            {
                GameObject newHex = (GameObject)Instantiate(hex);
                newHex.transform.Rotate(new Vector3(0,30,0));

            if (row == 0)
                {
                    newHex.transform.position = new Vector3(((i*hexWidth)+(hexWidth/2)),0,-(hexWidth/1.17f));
                }
            else
                {
                    newHex.transform.position = new Vector3((i*hexWidth)+((row+1)*(hexWidth/2)),0,(row+1)*-(hexWidth/1.17f));
                }
            }
    }

    for (int row = 0; row < startRowSize; row++)
    {
        for (int i = 0; i < startRowSize-1-row; i++)
            {
                GameObject newHex = (GameObject)Instantiate(hex);
                newHex.transform.Rotate(new Vector3(0,30,0));

            if (row == 0)
                {
                    newHex.transform.position = new Vector3(((i*hexWidth)+(hexWidth/2)),0,(hexWidth/1.17f));
                }
            else
                {
                    newHex.transform.position = new Vector3((i*hexWidth)+((row+1)*(hexWidth/2)),0,(row+1)*(hexWidth/1.17f));
                }
            }
    }
}

现在，有人可以建议如何清理它吗？我的大脑失败了......

Answer 2

只是一个提示，Awake发生在Start（）之前。

void Awake() 
{
   //5 mid
  startRowSize = 10;

  for (int i = 0; i < startRowSize; i++)
  {
      GameObject newHex = HexCreator();
      hexWidth = newHex.gameObject.renderer.bounds.size.z;
      newHex.transform.position = new Vector3(i * hexWidth, 0, 0);
  }

  for (int row = 0; row < startRowSize; row++)
     for (int i = 0; i < startRowSize-1-row; i++)
     {
         GameObject newHex = HexCreator();

         if (row == 0)
            newHex.transform.position = new Vector3(i*hexWidth + hexWidth/2, 0, -(hexWidth/1.17f));

         else
            newHex.transform.position = new Vector3(i*hexWidth + ((row+1)*(hexWidth/2)), 0,(row+1)*-(hexWidth/1.17f));
    }

  for (int row = 0; row < startRowSize; row++)
     for (int i = 0; i < startRowSize-1-row; i++)
     {
        GameObject newHex = HexCreator();

        if (row == 0)
            newHex.transform.position = new Vector3(i*hexWidth+ hexWidth/2, 0, hexWidth/1.17f);

        else
            newHex.transform.position = new Vector3(i*hexWidth + ((row+1)*(hexWidth/2)), 0, (row+1)*(hexWidth/1.17f));
     }
}

由于你重复了这段代码，我把它变成了一个函数。这样，如果您需要升级它，只需转到该功能并在那里进行更改。

private GameObject HexCreator()
{
    GameObject newHex = (GameObject)Instantiate(hex);
    newHex.transform.Rotate(new Vector3(0,30,0));

    return newHex;
}

嵌套循环 - 在Unity中生成一个catan样式的十六进制网格

2 个答案: