我正在使用数据库处理codeigniter项目,它在本地主机上运行完美,但是当我将它上传到真实服务器上时,出现了很多问题。
我真的做了很多搜索,但我找不到解决方案。
当我从数据库中检索数据时, result_array()函数无法正常工作并向我发出此错误" Fatal error: Call to a member function result() on a non-object in /home/mostafa/public_html/Sales/application/models/m_login.php on line 13 "
这是我的控制器代码
class c_login extends CI_Controller {
public function index() {
$this->load->view('login');
}
public function signin(){
$username = $this->input->post('username');
$password = $this->input->post('password');
$this->load->model('m_login');
$user = $this->m_login->signin($username, $password);
if(!$user){
echo "<script>alert('Your Username Or Password is Incorrect');</script>";
}else{
//set session
$userData = array(
'id' => $user[0]['id'],
'name' => $user[0]['name'],
'admin' => $user[0]['admin']
);
$this->session->set_userdata($userData);
if ($user[0]['admin'] == 1) {
redirect('c_home_admin');
}else{
redirect('c_home_user');
}
}
}
}
这是型号代码
class m_login extends CI_Model{
function insertUser($data) {
$this->db->insert('users', $data);
}
public function signin($username, $password){
$this->db->select('*')->from('users')->where(array('username' => $username, 'password' => $password));
$query = $this->db->get();
return $query->result_array();
}}
这是database.php配置:
$active_group = 'default';
$active_record = TRUE;
$db['default']['hostname'] = 'localhost';
$db['default']['username'] = 'root';
$db['default']['password'] = '**********';
$db['default']['database'] = 'mydb';
$db['default']['dbdriver'] = 'mysql';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
提前致谢
答案 0 :(得分:0)
我要检查的第一件事是你的数据库模式在开发时是否与实时完全相同。如果表格不相同(例如缺少字段),您将收到该错误。
修改强>
尝试按如下方式重写SQL查询:
$sql = "
SELECT * FROM `users` where `username` = ? AND `password` = ?
";
$q = $this->db->query($sql, array($username, $password));
return $q->result_array();
(抱歉 - 在我的回答中将其发布在此处,因为评论看起来很糟糕......)