SELECT CASE WHEN age IS NULL THEN 'Unspecified'
WHEN age < 18 THEN '<18'
WHEN age >= 18 AND age <= 24 THEN '18-24'
WHEN age >= 25 AND age <= 30 THEN '25-30'
WHEN age >= 31 AND age <= 40 THEN '31-40'
WHEN age > 40 THEN '>40'
END AS ageband,
COUNT(*)
FROM (SELECT age
FROM table) t
GROUP BY ageband
这是我的查询。这些是结果:
但是,如果table.age在一个类别中没有至少1个年龄,那么它将在结果中忽略该情况。像这样:
这个数据集没有任何年龄记录&lt;因此,年龄段“&lt; 18”没有出现。我怎样才能使它显示并返回一个值0 ??
答案 0 :(得分:10)
您需要一个agebands表来填充没有匹配行的条目的结果。这可以通过实际表来完成,或者使用如下子查询动态生成:
SELECT a.ageband, IFNULL(t.agecount, 0)
FROM (
-- ORIGINAL QUERY
SELECT
CASE
WHEN age IS NULL THEN 'Unspecified'
WHEN age < 18 THEN '<18'
WHEN age >= 18 AND age <= 24 THEN '18-24'
WHEN age >= 25 AND age <= 30 THEN '25-30'
WHEN age >= 31 AND age <= 40 THEN '31-40'
WHEN age > 40 THEN '>40'
END AS ageband,
COUNT(*) as agecount
FROM (SELECT age FROM Table1) t
GROUP BY ageband
) t
right join (
-- TABLE OF POSSIBLE AGEBANDS
SELECT 'Unspecified' as ageband union
SELECT '<18' union
SELECT '18-24' union
SELECT '25-30' union
SELECT '31-40' union
SELECT '>40'
) a on t.ageband = a.ageband
答案 1 :(得分:1)
我还没有测试过,但这应该可行。
SELECT ageband, cnt FROM (
SELECT '<18' as ageband, COUNT(*) as cnt FROMT table WHERE age < 18
UNION ALL
SELECT '18-24' as ageband, COUNT(*) as cnt FROMT table WHERE age >= 18 AND age <= 24
UNION ALL
SELECT '25-30' as ageband, COUNT(*) as cnt FROMT table WHERE age >= 25 AND age <= 30
UNION ALL
SELECT '31-40' as ageband, COUNT(*) as cnt FROMT table WHERE age >= 31 AND age <= 40
UNION ALL
SELECT '>40' as ageband, COUNT(*) as cnt FROMT table WHERE age > 40
) as A
答案 2 :(得分:0)
假设一个包含您的类别的表AgeCat。
SELECT c.Cat, COUNT(*) FROM Age a
RIGHT JOIN AgeCat c ON (
(a.age < 18 AND c.Cat = '<18')
OR (a.age BETWEEN 18 AND 24 AND c.Cat = '18-24')
OR (a.age BETWEEN 26 AND 30 AND c.Cat = '25-30')
-- etc.
) GROUP BY c.Cat;