Question

我有以下JavaScript数组：

 var days = [
            {
                "day": "sunday",
                "morning": "geschlossen",
            },
            {
                "day": "monday",
                "morning": "geschlossen",
            },
            {
                "day": "tuesday",
                "morning": "geschlossen",
            },
            {
                "day": "wenesday",
                "morning": "geschlossen",
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr",
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr",
            },
            {
                "day": "saturday",
                "morning": "geschlossen",
            }
        ];

如何更改数组中的0th index object到最后一个值？

所以我期望的数组将是这样的：

 var days = [               
            {
                "day": "monday",
                "morning": "geschlossen",
            },
            {
                "day": "tuesday",
                "morning": "geschlossen",
            },
            {
                "day": "wenesday",
                "morning": "geschlossen",
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr",
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr",
            },
            {
                "day": "saturday",
                "morning": "geschlossen",
            }, 
            {
                "day": "sunday",
                "morning": "geschlossen",
            }
        ];

我玩拼接和流行音乐，但没有任何意图。

Answer 1

您需要从数组的开头删除元素。 Array#shift这样做。然后，您需要将该元素添加到数组的末尾。 Array#push这样做。由于shift返回已移位的元素，因此您可以在一次调用中执行此操作：

days.push(days.shift());

影响数组的第一个和最后一个元素的关键函数是：

shift：从数组的开头删除一个元素
unshift：在数组的开头添加一个元素
pop：从数组末尾删除一个元素
push：在数组末尾添加一个元素

Answer 2

使用javascript shift和push功能 push函数在最后添加元素，shift函数删除并返回第一个元素

days.push(days.shift());

Answer 3

这个怎么样：

days.unshift(days.pop())

在编辑后编辑：

days.push(days.shift())

Answer 4

试试（未经测试）：

var days= [
            {
                "day": "sunday",
                "morning": "geschlossen"
            },
            {
                "day": "monday",
                "morning": "geschlossen"
            },
            {
                "day": "tuesday",
                "morning": "geschlossen"
            },
            {
                "day": "wenesday",
                "morning": "geschlossen"
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr"
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr"
            },
            {
                "day": "saturday",
                "morning": "geschlossen"
            }
        ];


var first = days[0];
days.shift();
days.push(first);
console.log(days);

将第一个对象推送到javascript数组中，使所有其他值保持不变

4 个答案: