如何从servlet获取数据到ajax并在JSP页面中使用

Question

window.onload = function() {
    alert("This is a onload function ...");
    var pass = window.dialogArguments; 
    var fields = pass.split(/~/);
    var userID = fields[0];
    $.ajax({
        type: "GET",
        async: false,
        dataType: "JSON",
        contentType: 'application/json',
        url: "/HostingProject/AdminCustServlet",
        data: {ActionType:"1",userID:userID},
        success: function(data ,textStatus, jqXHR){
        var splitString = data.split('|');
        $.each(splitString, function(i, item) {
        var tblRow = "<tr>" + "<td>" + item.AccountNumber + "</td>" + "<td>" +          item.AccountType + "</td>" + "<td>" + item.AccountStatus + "</td>" + "</tr>";
   $(tblRow).appendTo("#Account tbody");


            });
        }
    }
}); 
return values;
};

我编写了一个ajax函数，我将userID传递给servlet并检索accountno和accountType。我想在jsp页面中显示accountno和帐户类型，但我不能，它不起作用。请帮我。问候， 红宝石

<form action="HostingProject/AdminCustServlet" method="post">
  <table id="Account">
    <thead>
      <tr>
        <th>AccountNo</th>
        <th>AccountType</th>                    
      </tr>
    </thead>
    <tbody>

</tbody>
</table>

public void retrieve(HttpServletRequest request){
     //TODO Retrieve AccountnNo and AccountType
     PrintWriter out = response.getWriter();
     SIPAdminCustManager custManager = new SIPAdminCustManager();
     System.out.println("manager in retrieve");
     int userID = Integer.parseInt(request.getParameter("161"));
     List<String> acclist = custManager.retrieveAccountNamebyID(userID);
     System.out.println("got acclist"+acclist.size());
    Gson gson = new Gson();
String json = gson.toJson(acclist);
response.setContentType("Application/json");
response.getWriter().write(json);
System.out.println("json"+json);
}