Question

我正在使用NSOutlineView，我想显示第四个子级别。现在我只能显示三个子级别。

outlineViewController.m

 -(id)init{
     self = [super init];
     if(self){
         _people = [[NSMutableArray alloc]init];

         Person *quick = [[Person alloc]initWithName:@"First"];
         [quick addChild:[[Person alloc]initWithName:@"Second"]];
         [(Person *)[quick.children objectAtIndex:0]addChild:[[Person alloc]initWithName:@"Third"]];

         [_people addObject:quick];

     }
     return self; 
 }

person.m

-(id)init{
     return [self initWithName:@"Name"]; 
 }


 -(id)initWithName:(NSString *)name {
         self = [super init];
         if(self){
             _name = [name copy];
             _children = [[NSMutableArray alloc]init];

         }
         return self; 
     }

 -(void)addChild:(Person *)p {
     [_children addObject:p];
 }

person.h

 @property (copy)NSString *name;
 @property(readonly,copy)NSMutableArray *children;
 -(id)initWithName:(NSString *)name;
 -(void)addChild:(Person *)p;

我得到的结果是这样的。

>First
   >Second
      Third

我想要像这样输出..

>First
   >Second
      >Third
         >Fourth
            Fifth

谢谢。

Answer 1

您正在将孩子添加到第二位：

[(Person *)[quick.children objectAtIndex:0]addChild:[[Person alloc]initWithName:@"Third"]];

同样，您可以将child添加到第三个：

[(Person*)[((Person *)[quick.children objectAtIndex:0]).children objectAtIndex:0]addChild:[[Person alloc]initWithName:@"Fourth"]];

然后以第四名：

 [(Person*)[((Person*)[((Person *)[quick.children objectAtIndex:0]).children objectAtIndex:0]).children objectAtIndex:0] addChild:[[Person alloc]initWithName:@"Fifth"]];

或者为了简单起见，首先创建最低级别的对象，然后将其作为子级添加到其父级：

Person *fifth = [[Person alloc]initWithName:@"Fifth"]; 
Person *fourth = [[Person alloc]initWithName:@"Fourth"];
[fourth addChild: fifth];
Person *third = [[Person alloc]initWithName:@"Third"];
[third addChild: fourth];
Person *second = [[Person alloc]initWithName:@"Second"];
[second addChild: third];
Person *quick = [[Person alloc]initWithName:@"First"];
[quick addChild: second];

NSOutlineView显示三个级别

1 个答案: