重新分配结构会导致程序崩溃

时间:2013-11-12 20:54:47

标签: c++ memory-management

所以我试图从矢量结构中释放内存。当矢量为3或更小时,它工作正常。但是,当它达到4或更高,并且我尝试调用deallocate函数时,它会崩溃。我不完全确定我是否正在进行正确的解构,我需要提示一下它在哪里出错......

void dealloc_vec(Vector * myVector)
{


myVector->size = 0;
//Delete the array of Vectors.
delete(myVector->vectorArray);
//Finally delete the entire vector.
delete(myVector);
}

我的结构就是这个

struct Vector
{
unsigned int size;
Elem *vectorArray;
};

Elem是一个浮动。每当创建大于3的大小时,它会在退出之前崩溃程序。我们正在使用程序化c ++。

Vector *alloc_vec(void)
{
//create a vector
Vector *temp_Vector = new Vector();

//Using getInt from above to grab values for the size of vector, if given 0 it will just be a 0 vector.
temp_Vector->size = getInt((char*)"Please enter a value: ");
/*Test to see if it is less than zero, if it is program will halt.
assert(temp_Vector->size >= 0);
No need to check as unsigned int cannot be negative according to Wtype-limits
The size of vectorArray is now initialized from the size parameter of the structure.*/
temp_Vector->vectorArray =  new float(temp_Vector->size);

//Loop through each element and assign a value from the user using getFloat (It looks cleaner         with having separate functions).
for(unsigned int i = 0; i < temp_Vector->size; i++)
{
    printf("Vector Element %d: ",i);
    temp_Vector->vectorArray[i] = getFloat((char*)"");
}
//return the new vector.
return temp_Vector;


}

getFloat和getInt

float getFloat(char* promptMessage)
{
assert(promptMessage != NULL);
float myInput;
char size[100];
bool sucessful = false;

do
{
    printf("%s", promptMessage);
    //Use fgets to get the input from stdin.
    fgets(size, 100, stdin);
    //Check if value is anything but zero, if it isn't use this.
    if(sscanf(size, "%f", &myInput) == 1)
    {

        myInput = atof(size);
        sucessful = true;
    }
    else
    {
        printf("\nPlease enter a correct number: ");
    }
}while(!sucessful);


return myInput;
}

int getInt(char* promptMessage)
{
assert(promptMessage != NULL);
int myInput;
char size[100];
bool sucessful = false;

do
{
    printf("%s", promptMessage);
    fgets(size, 100, stdin);
    //Get the size using fgets and sscanf
    sscanf(size, "%i", &myInput);

    //Size cannot be greater than 65535 or less than 0.
    if(atoi(size) > 65535)
    {
        printf("The chosen value is too large!\n");
    }
    else if(atoi(size) < 0)
    {
        printf("Error! Value is too small!\n");
    }
    //If sscanf is anything but a number, don't do this.
    else if(sscanf(size, "%i", &myInput) == 1)
    {

        myInput = atoi(size);
        sucessful = true;
    }
    else
    {
        printf("\nPlease enter a correct number: ");
    }
}while(!sucessful);

return myInput;
}

3 个答案:

答案 0 :(得分:1)

如果您按[] new Elem [x]分配了它,那么您应该通过

取消分配它
delete [] myVector->vectorArray;

您可以使用std::vector来简化编码。甚至是std::unique_ptr

std::unique_ptr<Elem[]> vectorArray(new Elem[x]);

答案 1 :(得分:0)

struct中添加一个构造函数,用于初始化成员。 vectorArray最初指向随机内存位置,删除这些位置将导致未定义的行为。

struct Vector
{
  Vector() : size(0), vectorArray(NULL) {}

  unsigned int size;
  Elem *vectorArray;
};

答案 2 :(得分:0)

试试这个

Vector *alloc_vec(void)
{
  //create a vector
  Vector *temp_Vector = new Vector;  // don't use ()

  temp_Vector->size = getInt((char*)"Please enter a value: ");
  temp_Vector->vectorArray =  new float[temp_Vector->size];

  for(unsigned int i = 0; i < temp_Vector->size; i++)
  {
    printf("Vector Element %d: ",i);
    temp_Vector->vectorArray[i] = getFloat((char*)"");
  }
  return temp_Vector;
}

然后在dealloc

void dealloc_vec(Vector * myVector)
{
  myVector->size = 0; // there is no need for this
  //Delete the array of Vectors.
  delete [] myVector->vectorArray;  // no need for the ()
  //Finally delete the entire vector.
  delete myVector;
}

编辑:

你的getInt / getFloat看起来有点不对

sscanf(size, "%i", &myInput);
//Size cannot be greater than 65535 or less than 0.
if(atoi(size) > 65535)

而只是做这样的事情

int getInt(const char* prompt) 
{ 
  int n = 0;
  char buf[32]; 
  do
  {
    printf( "%s", prompt ); 
    fgets( buf, sizeof(buf), stdin ); 
    n = atoi(buf); // will ignore the \n
  }
  while ( n > 65535 );
  return n; 
}

for float只需用atof替换atoi(如果合适,可以使用限制)。请注意,如果输入文本,atoi和atof将返回0,因此您可能需要检查是否> 0