我需要的目标是获取最后一个回复来自用户而不是管理员的票据,最后一个回复是10天或更长时间。我目前有一个SQL获得最后的回复,但我很难从管理员过滤用户。我当前的SQL是:
SELECT
t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
JOIN (
SELECT
tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
FROM ticket_reply tr_last
ORDER BY tr_last.reply_date DESC
) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid
WHERE
t.status != "Closed"
AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date
GROUP BY t.tid;
返回类似于:
的内容+-------+---------------------+-------+-----------------------------+-----------+
| tid | reply_date | rid | display_name | user_type |
+-------+---------------------+-------+-----------------------------+-----------+
| 6784 | 2012-03-27 04:11:52 | 40061 | (hidden) | admin |
| 8094 | 2013-01-18 21:13:56 | 65037 | (hidden) | admin |
| 8165 | 2012-09-10 14:59:17 | 52956 | (hidden) | admin |
| 8171 | 2012-06-18 19:05:19 | 46527 | (hidden) | user |
| 8313 | 2012-08-16 23:05:51 | 51362 | (hidden) | admin |
| 8436 | 2012-08-16 23:20:20 | 51368 | (hidden) | admin |
| 8453 | 2012-06-26 23:41:37 | 47247 | (hidden) | admin |
| 8712 | 2012-11-22 10:33:05 | 59697 | (hidden) | user |
| 8911 | 2013-09-24 00:52:27 | 89910 | (hidden) | user |
| 8949 | 2013-09-02 16:29:22 | 87718 | (hidden) | user |
+-------+---------------------+-------+-----------------------------+-----------+
如果我在u.user_type = "user"
子句中添加WHERE
,则会更改其检索到的tr
中的哪一行,以便现在6784
tid
行中的用户显示用户不是管理员,但该票证的最后一个回复实际上是管理员。所以这个:
SELECT
t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
JOIN (
SELECT
tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
FROM ticket_reply tr_last
ORDER BY tr_last.reply_date DESC
) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid
WHERE
t.status != "Closed"
AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date
AND u.user_type = "user"
GROUP BY t.tid;
现在返回:
+-------+---------------------+-------+-----------------------------+-----------+
| tid | reply_date | rid | display_name | user_type |
+-------+---------------------+-------+-----------------------------+-----------+
| 6784 | 2012-03-26 23:19:52 | 40051 | (hidden) | user |
| 8094 | 2013-01-18 18:53:33 | 65016 | (hidden) | user |
| 8165 | 2012-09-07 01:17:28 | 52831 | (hidden) | user |
| 8171 | 2012-06-18 19:05:19 | 46527 | (hidden) | user |
| 8313 | 2012-08-09 18:37:35 | 50776 | (hidden) | user |
| 8436 | 2012-08-16 23:01:28 | 51359 | (hidden) | user |
| 8453 | 2012-06-21 16:29:24 | 46843 | (hidden) | user |
| 8712 | 2012-11-22 10:33:05 | 59697 | (hidden) | user |
| 8911 | 2013-09-24 00:52:27 | 89910 | (hidden) | user |
| 8949 | 2013-09-02 16:29:22 | 87718 | (hidden) | user |
+-------+---------------------+-------+-----------------------------+-----------+
您可以注意到rid
列值也不同。
所以我的问题是,如何为此正确地返回用户?
答案 0 :(得分:2)
你没有在任何地方得到最后的回复。在子查询中,您只是对值进行排序。
尝试这样的事情:
SELECT t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
INNER JOIN (
SELECT tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
FROM ticket_reply tr_last
INNER JOIN (
SELECT tid, max(reply_date)
FROM ticket_reply
GROUP BY tid
) tr2 ON tr2.tid = tr_last.tid AND tr_last.reply_date = tr2.reply_date
) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid AND u.user_type = "user"
WHERE t.STATUS != "Closed"
AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date;
内部查询返回tid及其MAX(日期),并提供最新的回复信息。
(我没有测试过这个,但看起来像你在找什么)。