Question

我们的库存存在问题，我们有一个余额列，可以在交易发生时添加或减少。有一些问题我们无法追踪，因此已经做出了改变，通过增加和减去（在适当的情况下）移动数量并达到今天的股票价值来计算股票。

但是现在，结构是这样的，一个产品有多个股票，因此产品A到期时间为01 / 2012,02 / 2013等。

我目前创建了一个查询，根据产品的一个库存，它将按如下方式计算当前库存：

select
(select ISNULL(sum(gd.qty),0) as grnadd from grns as g
INNER JOIN grndetails as gd ON g.id = gd.grnid
INNER JOIN stocks as s ON s.id = gd.stockid
where g.locationid = 10 and s.prodid =2653)
-
(select ISNULL(sum(cod.qty), 0) as salesub from salesorders as co
INNER JOIN salesorddetails as cod ON co.id = cod.cusordid
INNER JOIN stocks as s ON s.id = cod.stockid
where co.status != 'cancel' and co.locid = 10 and s.prodid =2653)
-
(select ISNULL(sum(cod.qty), 0) as cussub from customerorders as co
INNER JOIN customerorddetails as cod ON co.id = cod.cusordid
INNER JOIN stocks as s ON s.id = cod.stockid
where co.status != 'cancel' and co.locid = 10 and s.prodid =2653)

因此，在这种情况下，会计算一种产品的库存，但是我可以在第二列中列出所有产品及其总计（如上所述）的查询吗？

谢谢，希望从上面的查询中了解结构

编辑：

股票表：id，prodid，expiry

产品表：id，商品名称

GRN详细信息表：id，grnid，qty，stockid（因为它影响股票而非产品）

销售＆amp;客户订单详细信息表：id，cusordid，qty，stockid

GRN＆amp;销售＆amp; Cus Ord表：id，locid

位置表：id，locname

Answer 1

尝试包含所有产品ID并按其分组。这是一些建议的代码

select prodid, sum(total) as total from (
       (select s.prodid
             , ISNULL(sum(gd.qty),0) as total
          from grns as g
               INNER JOIN grndetails as gd 
               ON g.id = gd.grnid
               INNER JOIN stocks as s 
               ON s.id = gd.stockid
         where g.locationid = 10 group by s.prodid)
union all
       (select s.prodid
             , ISNULL(sum(cod.qty), 0)*(-1) as total 
          from salesorders as co
               INNER JOIN salesorddetails as cod 
               ON co.id = cod.cusordid
               INNER JOIN stocks as s 
               ON s.id = cod.stockid
         where co.status != 'cancel' 
           and co.locid = 10 group by s.prodid)
union all
       (select s.prod_id
             , ISNULL(sum(cod.qty), 0)*(-1) as total
          from customerorders as co
               INNER JOIN customerorddetails as cod 
               ON co.id = cod.cusordid
               INNER JOIN stocks as s 
               ON s.id = cod.stockid
         where co.status != 'cancel' 
           and co.locid = 10 group by s.prodid)
) as x
group by prodid

我已将所有缺点更改为union-alls，以便不会相互减去product-id，并且将根据您的product -ID计算总计。

Answer 2

试试这个：

WITH
    S AS (
        SELECT DISTINCT prodid FROM stocks
    ),
    L AS (
        /* SELECT 10 AS locationid */
        SELECT DISTINCT locationid FROM grns
    ),
    T1 AS (
        select 
            g.locationid, 
            s.prodid,
            sum(gd.qty) as grnadd 
        from grns as g 
        INNER JOIN grndetails as gd ON g.id = gd.grnid
        INNER JOIN stocks as s ON s.id = gd.stockid
        GROUP BY g.locationid, s.prodid
    ),
    T2 AS (
        select 
            co.locid as locationid,
            s.prodid,
            sum(cod.qty) as salesub 
        from salesorders as co
        INNER JOIN salesorddetails as cod ON co.id = cod.cusordid
        INNER JOIN stocks as s ON s.id = cod.stockid
        where co.status != 'cancel'
        GROUP BY co.locid, s.prodid
    ),
    T3 AS (
        select 
            co.locid as locationid,
            s.prodid,
            sum(cod.qty) as cussub 
        from customerorders as co
        INNER JOIN customerorddetails as cod ON co.id = cod.cusordid
        INNER JOIN stocks as s ON s.id = cod.stockid
        where co.status != 'cancel'
        GROUP BY co.locid, s.prodid
    )
SELECT 
    S.prodid, L.locationid, ISNULL(grnadd, 0) - ISNULL(salesub, 0) - ISNULL(cussub, 0)
FROM
    S CROSS JOIN
    L LEFT OUTER JOIN
    T1 ON T1.locationid = L.locationid AND T1.prodid = S.prodid LEFT OUTER JOIN
    T2 ON T2.locationid = L.locationid AND T2.prodid = S.prodid LEFT OUTER JOIN
    T3 ON T3.locationid = L.locationid AND T3.prodid = S.prodid

我认为该位置可能也很重要，因此返回3列。如果您只希望结果为ID为10的位置，则在L CTL取消注释第一行并注释第二行。

Answer 3

假设您的数据模型很多（希望我理解正确的问题），group by可能就是答案：

select
(select s.prodid, ISNULL(sum(gd.qty),0) as grnadd from grns as g
INNER JOIN grndetails as gd ON g.id = gd.grnid
INNER JOIN stocks as s ON s.id = gd.stockid
where g.locationid = 10 
GROUP BY s.prodid)
-
(select s.prodid, ISNULL(sum(cod.qty), 0) as salesub from salesorders as co
INNER JOIN salesorddetails as cod ON co.id = cod.cusordid
INNER JOIN stocks as s ON s.id = cod.stockid
where co.status != 'cancel' and co.locid = 10
GROUP BY s.prodid)
-
(select s.prodid, ISNULL(sum(cod.qty), 0) as cussub from customerorders as co
INNER JOIN customerorddetails as cod ON co.id = cod.cusordid
INNER JOIN stocks as s ON s.id = cod.stockid
where co.status != 'cancel' and co.locid = 10
GROUP BY s.prodid)

使用SQL计算多个表事务的库存数量

3 个答案: