Question

我有3张桌子：

银行
bank_details
bank_bank_details

他们之间的关系：

银行模式：

public function relations() {
        return array(
            'bankBankDetails' => array(self::HAS_MANY, 'BankBankDetails', 'bank_id'),
        );
}

bank_details模型：

public function relations() {
        return array(
            'bankBankDetails' => array(self::HAS_MANY, 'BankBankDetails', 'bank_details_id'),
        );
    }

bank_bank_details型号：

public function relations()
    {
        return array(
            'bank' => array(self::BELONGS_TO, 'Bank', 'bank_id'),            
            'bankDetails' => array(self::BELONGS_TO, 'BankDetails', 'bank_details_id'),
        );
    }

我想在 bank_details 模型的管理视图中获取银行详细信息，例如bank_name，ifsc etc info。

我生成的普通SQL查询非常正常：

SELECT b.name
FROM bank b
LEFT JOIN bank_bank_details bbd ON bbd.bank_id = b.bank_id
LEFT JOIN bank_details bd ON bd.bank_details_id = bbd.bank_details_id
WHERE bd.bank_details_id = bbd.bank_details_id
LIMIT 0 , 30

现在我只想将它与Yii CDBCriteria整合，但它不适合我。请检查以下代码：

public function search() {
        $criteria = new CDbCriteria;    
//        select b.name
//        from bank b
//        left join bank_bank_details bbd
//        on bbd.bank_id = b.bank_id
//        left join bank_details bd on bd.bank_details_id = bbd.bank_details_id
//        WHERE bd.bank_details_id = bbd . bank_details_id;

        $criteria->compare('bank_details_id', $this->bank_details_id);
        $criteria->compare('first_holder_name', $this->first_holder_name, true);
        $criteria->compare('nominee1', $this->nominee1, true);
        $criteria->select = 'b.name';
        $criteria->join = 'LEFT JOIN bank_bank_details bbd ON bbd.bank_id = b.bank_id ';
        $criteria->join .= 'LEFT JOIN bank_details bd ON bd.bank_details_id = bbd.bank_details_id';
        $criteria->condition = 'bd.bank_details_id = bbd.bank_details_id';

        return new CActiveDataProvider($this, array(
            'criteria' => $criteria,
            'pagination' => array(
                'pageSize' => 10,
            ),
        ));
    }

错误： 发现错误500 CDbCommand无法执行SQL语句：SQLSTATE [42S22]：找不到列：1054'on clause'中的未知列'b.bank_id'

任何帮助都将不胜感激。

Answer 1

您需要像这样为表设置别名： $criteria->alias='b';或使用默认别名“t”而不是“b”

阅读更多内容 http://www.yiiframework.com/doc/api/1.1/CDbCriteria#alias-detail

Answer 2

尝试：

public function search() {
    $criteria = new CDbCriteria;    
    $criteria->compare('bank_details_id', $this->bank_details_id);
    $criteria->compare('first_holder_name', $this->first_holder_name, true);
    $criteria->compare('nominee1', $this->nominee1, true);
    $criteria->select = 'bank.name';
    $criteria->with = array(
         'bankBankDetails' => array('joinType'=>'LEFT JOIN'),
         'bankBankDetails.bank' => array('joinType'=>'LEFT JOIN'),
    );
    $criteria->addCondition('t.bank_details_id = bankBankDetails.bank_details_id');

    return new CActiveDataProvider($this, array(
        'criteria' => $criteria,
        'pagination' => array(
            'pageSize' => 10,
        ),
    ));
}

主表（在FROM中）具有别名t，在compare之后你已经有了一些条件，而不是你需要添加到现有的，而不是重写

<强>更新

如果您从模型bank_details进行查询，则主表（FROM）必须为bank_details。查询将是：

SELECT b.name
FROM bank_details bd
LEFT JOIN bank_bank_details bbd ON bd.bank_details_id = bbd.bank_details_id
LEFT JOIN bank b bbd ON bbd.bank_id = b.bank_id
WHERE bd.bank_details_id = bbd.bank_details_id
LIMIT 0 , 30

Answer 3

这里 $criteria->select = 'b.name'; 您只选择银行名称而未选择ID

不确定yii格式是否类似

$criteria->select = 'b.name,b.bank_id';

或

$criteria->select = array('b.name,b.bank_id');

Answer 4

正如@Evgeniy所提到的，您需要使用$criteria->alias = 'b';

设置别名

http://www.yiiframework.com/doc/api/1.1/CDbCriteria#alias-detail

您可能还想查看使用CDbCriteria::with您可以使用它来选择相关模型。

http://www.yiiframework.com/doc/api/1.1/CDbCriteria#with-detail

如果您使用上述内容，请确保您也正确使用CDbCriteria::together。要一次选择所有相关模型，请将其设置为true;

http://www.yiiframework.com/doc/api/1.1/CDbCriteria#together-detail

Yii CDBCriteria复合加入查询

4 个答案: