我有一个包含超过700个属性的大型Object。我如何遍历每个编号的属性?
{ '0':
{ emails:
{ categorized: [Object],
all: [Object],
primary: 'support@wish.com' },
id: '290cb70ea0f',
updated: '2011-09-16T05:55:12.136Z' },
'1':
{ emails:
{ categorized: [Object],
all: [Object],
primary: 'VJONO@csnfo.com' },
id: '753ac508e1a00e',
updated: '2012-07-12T22:23:11.196Z' },
'2':
{ title: 'Bryan Weston',
phone_numbers: { categorized: [Object], all: [Object], primary: '' },
id: 'b4c0268d92825e',
updated: '2010-10-13T08:00:32.834Z' },
// It goes on....
答案 0 :(得分:2)
使用下划线。
_.each(yourObject, function (item, index) {
console.log(item.emails);
console.log(item.title);
// etc...
});
答案 1 :(得分:2)
在纯JavaScript中,它会像这样
var data = { /*stuff*/ };
var item;
for (var prop in data) {
//hasOwn is probably not needed
if( /*data.hasOwnProperty(prop) &&*/ !isNaN(prop) ) { //only do stuff if the property is a number
item = data[prop];
//work
}
}
使用Underscore,您可以按照Mark的回答编写,但使用类似的if(!isNaN(prop))
或_.isNaN
支票
答案 2 :(得分:0)
试试这个:
var objectKeys = Object.keys(yourObject).map(Number);
objectKeys.sort();
for(var i=0;i < objectKeys.length; i++) {
key = objectKeys[i];
element = yourObject[key];
//do magic here
}
如果您不关心处理顺序,可以使用for(key in youObject)