Question

学习Java我当前的问题是使用下面的“else”语句。我要找的结果是，如果我输入3小时55分钟：“五到四”

根据以下代码，我得到： 请输入小时数（1到12之间）： 3 请输入分钟（1到60之间）： 55 五到三

有人可以告诉我，我做错了什么吗？（感谢）

// actual calcuations

    if(minuteValue==0){
        result = hourPart + minutePart + " o'clock"; // eg two o'clock (the String o'clock defined later in the minute values)
    }
    else if (minuteValue <= 30 ){
        result = minutePart + " past " + hourPart; // eg ten past five
    }
    else
    {
       int remainingtime = 60 - minuteValue;
       int nexthr = hourValue + 1;
       if(nexthr==13) nexthr = 1;  

       result = getHourString(remainingtime) + " to " + hourPart; // eg twenty to five

    }

    return result;

Answer 1

首先，您没有使用nexthr：

result = getHourString(remainingtime) + " to " + hourPart; //where's nexthr?

其次，你可以在这里找到很多东西。只需hourValue和minuteValue即可跟踪输入的时间。将minutePart更改为minuteValue，将hourPart更改为hourValue，您就完成了：

String result;
int minuteValue = 55;
int hourValue = 9;

if(minuteValue==0){
    result = hourValue + minuteValue + " o'clock"; // eg two o'clock (the String o'clock defined later in the minute values)
}
else if (minuteValue <= 30 ){
    result = minuteValue + " past " + hourValue; // eg ten past five
}
else
{
   int remainingtime = 60 - minuteValue;
   int nexthr = hourValue + 1;
   if(nexthr==13) nexthr = 1;  
   result = remainingtime + " to " + nexthr; // eg twenty to five

}

System.out.println(result);

结果：5 to 10

Answer 2

String result;
int minuteValue = 55;
int hourValue = 9;

if(minuteValue==0){
    result = hourValue + minuteValue + " o'clock"; // eg two o'clock (the String o'clock defined later in the minute values)
}
else if (minuteValue <= 30 ){
    result = minuteValue + " past " + hourValue; // eg ten past five
}
else
{
   int remainingtime = 60 - minuteValue;
   int nexthr = hourValue + 1;
   if(nexthr==13) nexthr = 1;  
   result = remainingtime + " to " + nexthr; // eg twenty to five

}

System.out.println(result);

计算小时加1

2 个答案: