Question

我有一张表格列出了一些案例，并指定了主要和二级技术人员。我想要完成的是汇总技术人员作为主要和次要技术工作的案例数量。应该看起来像这样...

Technician     Primary     Secondary
John             4              3
Stacy            3              1
Michael          5              3

我从中提取数据的表格如下所示：

CaseID, PrimaryTech, SecondaryTech, DOS

过去我曾经使用过这样的东西，但现在我的上司也在询问次要案件的数量......

SELECT PrimaryTech, COUNT(CaseID) as Total
GROUP BY PrimaryTech

我已经做了一些搜索，但似乎无法找到问题的答案。

Answer 1

Select Tech, 
       sum(case when IsPrimary = 1 then 1 else 0 end) as PrimaryCount,
       sum(case when IsPrimary = 0 then 1 else 0 end) as SecondaryCount
from
(
  SELECT SecondaryTech as Tech, 0 as IsPrimary
  FROM your_table
  union all
  SELECT PrimaryTech as Tech, 1 as IsPrimary
  FROM your_table
) x
GROUP BY Tech

Answer 2

您可以将两个子查询与FULL JOIN组合在一起，如SQLFiddle所示。

SELECT Technician = COALESCE(pri.Technician, sec.Technician)
    , PrimaryTech
    , SecondaryTech
FROM 
    (SELECT Technician = PrimaryTech
        , PrimaryTech = COUNT(*)
    FROM Cases
    WHERE PrimaryTech IS NOT NULL
    GROUP BY PrimaryTech) pri
FULL JOIN
    (SELECT Technician = SecondaryTech
        , SecondaryTech = COUNT(*)
    FROM Cases
    WHERE SecondaryTech IS NOT NULL
    GROUP BY SecondaryTech) sec
    ON pri.Technician = sec.Technician
ORDER By Technician;

Answer 3

SELECT COALESCE(A.NAME, B.NAME) AS NAME, CASE WHEN A.CASES IS NOT NULL THEN A.CASES ELSE 0 END AS PRIMARY_CASES,
CASE WHEN B.CASES IS NOT NULL THEN B.CASES ELSE 0 END AS SECONDARY_CASES
FROM
(
SELECT COUNT(*) AS CASES, PRIMARYTECH AS NAME FROM YOUR_TABLE
GROUP BY PRIMARYTECH
) AS A
FULL OUTER JOIN
(
SELECT COUNT(*) AS CASES, SECONDARYTECH AS NAME FROM YOUR_TABLE
GROUP BY SECONDARYTECH
) AS B
ON A.NAME = B.NAME

SQL聚合函数

3 个答案: