Question

如何在WCF的帮助下通过帖子发送xml数据？

例如我有一些代码：

public interface IServiceForILobby
{
    [OperationContract]
    [WebInvoke(Method = "POST")] 
    string SendXml(string response);
}

//这是主持人

static void Main(string[] args)
{
    Console.WriteLine("*Console Based Rest HOST*");

    using (WebServiceHost serviceHost = new WebServiceHost(typeof(ServiceForILobby)))
    {
        serviceHost.Open();
        Console.ReadLine();                
    }

/ *这是Client * /

using (ChannelFactory<IServiceForILobby> cf = new   ChannelFactory<IServiceForILobby>(new WebHttpBinding(), "http://192.168.1.103:50000/RestService/SendXml?response={x}"))
{
    cf.Endpoint.EndpointBehaviors.Add(new WebHttpBehavior());
    IServiceForILobby channel = cf.CreateChannel();
    string s;
    // s = channel.SendXml("http://192.168.1.103:50000/RestService/SendXml?response={x}");
    string a;

    using (StreamReader sr = new StreamReader("simplexml.txt"))
    {
        string xmlCode = sr.ReadToEnd();
        s = channel.SendXml(xmlCode);
    }

我想将XML从客户端发送到主机，然后像这样解析How does one parse XML files?

Answer 1

为了通过POST发送xml数据，您需要根据WCF服务正确构建数据。这基本上是你需要的：

1）WCF服务接口

[OperationContract]
[WebInvoke(Method = "POST",
    UriTemplate = "GetData",
    RequestFormat = WebMessageFormat.Xml,
    BodyStyle = WebMessageBodyStyle.Bare)]
string GetData(DataRequest parameter);

2）WCF服务实施

public string GetData(DataRequest parameter)
{
    //Do stuff
    return "your data here";
}

3）WCF服务中的数据合同（在本例中为DataRequest）

[DataContract(Namespace = "YourNamespaceHere")]
public class DataRequest
{
    [DataMember]
    public string ID{ get; set; }
    [DataMember]
    public string Data{ get; set; }
}

4）发送数据的客户必须正确构建数据！（在这种情况下是C＃console app）

static void Main(string[] args)
{
    ASCIIEncoding encoding = new ASCIIEncoding();
    string SampleXml = "<DataRequest xmlns=\"YourNamespaceHere\">" +
                                    "<ID>" +
                                    yourIDVariable +
                                    "</ID>" +
                                    "<Data>" +
                                    yourDataVariable +
                                    "</Data>" +
                                "</DataRequest>";

    string postData = SampleXml.ToString();
    byte[] data = encoding.GetBytes(postData);

    string url = "http://localhost:62810/MyService.svc/GetData";

    string strResult = string.Empty;

    // declare httpwebrequet wrt url defined above
    HttpWebRequest webrequest = (HttpWebRequest)WebRequest.Create(url);
    // set method as post
    webrequest.Method = "POST";
    // set content type
    webrequest.ContentType = "application/xml";
    // set content length
    webrequest.ContentLength = data.Length;
    // get stream data out of webrequest object
    Stream newStream = webrequest.GetRequestStream();
    newStream.Write(data, 0, data.Length);
    newStream.Close();

    //Gets the response
    WebResponse response = webrequest.GetResponse();
    //Writes the Response
    Stream responseStream = response.GetResponseStream();

    StreamReader sr = new StreamReader(responseStream);
    string s = sr.ReadToEnd();

    return s;
}

Answer 2

c#-corner的以下代码段提供了一个很好的示例：

    string postData = SampleXml.ToString();
    // convert xmlstring to byte using ascii encoding
    byte[] data = encoding.GetBytes(postData);
    // declare httpwebrequet wrt url defined above
    HttpWebRequest webrequest = (HttpWebRequest)WebRequest.Create(url);
    // set method as post
    webrequest.Method = "POST";
    // set content type
    webrequest.ContentType = "application/x-www-form-urlencoded";
    // set content length
    webrequest.ContentLength = data.Length;
    // get stream data out of webrequest object
    Stream newStream = webrequest.GetRequestStream();
    newStream.Write(data, 0, data.Length);
    newStream.Close();
    // declare & read response from service
    HttpWebResponse webresponse = (HttpWebResponse)webrequest.GetResponse();

如何使用wcf通过post发送xml

2 个答案: