Question

我正在使用Parse为应用程序创建登录页面。我收到错误“可见@interface for'UIResponder'声明选择器'viewDidAppear'” 我也得到“可见@interface for'UIResponder'声明选择器'presentViewController：animated：present'”

所以，在我的AppDelegate.m中，我有：

 - (void)viewDidAppear:(BOOL)animated {
    [super viewDidAppear:animated];//I GET THE ERROR HERE

    if (![PFUser currentUser]) { // No user logged in
        // Create the log in view controller
        PFLogInViewController *logInViewController = [[PFLogInViewController alloc] init];
        [logInViewController setDelegate:self]; // Set ourselves as the delegate

        // Create the sign up view controller
        PFSignUpViewController *signUpViewController = [[PFSignUpViewController alloc] init];
        [signUpViewController setDelegate:self]; // Set ourselves as the delegate

       // Assign our sign up controller to be displayed from the login controller
        [logInViewController setSignUpController:signUpViewController];

        // Present the log in view controller
        [self presentViewController:logInViewController animated:YES completion:NULL];//I GET THE ERROR HERE

        }
    }

在我的AppDelegate.h中：

#import <UIKit/UIKit.h>
#import <Parse/Parse.h>

@interface AppDelegate : UIResponder <UIApplicationDelegate>

@property (strong, nonatomic) UIWindow *window;

@end

// Implement both delegates
@interface DefaultSettingsViewController :
    UIViewController <PFLogInViewControllerDelegate, PFSignUpViewControllerDelegate>
@end

我该如何解决此问题？

Answer 1

您的超类需要是UIViewController子类。在您的代码中，它是UIResponder子类。

但我认为原因是你将应该放在视图控制器中的代码放入app委托。将viewDidAppear:方法移动到视图控制器所在的位置。

'UIResponder'没有可见的@interface声明选择器'viewDidAppear'

1 个答案: