嗯，问题是，我需要在python中使用字典，但我意识到我无法随机地改变它们。我必须随机改组它，并将值分配给同一个字典。任何帮助将不胜感激。
import random
i = 1
name = ""
helper = []
number_of_com = 0
win_0 = []
win_1 = []
win_2 = []
win_3 = []
win_4 = []
win_5 = []
win_6 = []
win_7 = []
win_8 = []
win_9 = []
win_10 = []
print ("Welcome to the Swiss Round Calculator. This project was made by Enes Kristo")
number_of_com = int(input("Please enter the number of the competitors:\n"))
if number_of_com <= 16:
loop = 3
elif number_of_com <= 32:
loop = 4
elif number_of_com <= 64:
loop = 5
elif number_of_com <= 128:
loop = 6
elif number_of_com <= 256:
loop = 7
elif number_of_com <= 512:
loop = 8
elif number_of_com <= 1024:
loop = 9
else:
loop = 10
while i <= number_of_com:
name = str(input("Name of competitor nr."+str(i)+":\n"))
helper.append([name, 0, 0])
i += 1
def odd():
b = 0
while b <= (number_of_com - 2):
helper_1 = helper[b]
b += 1
helper_2 = helper[b]
print ("Player " + str(helper_1[0]) + " is vs player " + str(helper_2[0]) + ".")
b += 1
helper_3 = helper[(number_of_com-1)]
print (str(helper_3[0])+" gets a free win.")
helper_3[1] += 1
helper[(number_of_com-1)] = helper_3
b = 0
while b <= (number_of_com - 2):
helper_1 = helper[b]
b += 1
helper_2 = helper[b]
print("In the match between player " + str(helper_1[0]) + " and player " +str(helper_2[0]) + " who won?")
a = int(input("Enter 1 if player " + str(helper_1[0]) + " won or 2 if player " + str(helper_2[0]) + " won.\n"))
if a == 1 or a == 2:
if a == 1:
helper_1[1] += 1
helper_2[2] += 1
b -= 1
helper[b] = helper_1
b += 1
helper[b] = helper_2
else:
helper_1[2] += 1
helper_2[1] += 1
b -= 1
helper[b] = helper_1
b += 1
helper[b] = helper_2
else:
print("Enter a correct number.")
b -= 1
continue
b += 1
random.shuffle(helper)
v = 0
while v < number_of_com:
helper_1 = helper[v]
if helper_1[1] == 0:
win_0.append(helper_1)
elif helper_1[1] == 1:
win_1.append(helper_1)
elif helper_1[1] == 2:
win_2.append(helper_1)
elif helper_1[1] == 3:
win_3.append(helper_1)
elif helper_1[1] == 4:
win_4.append(helper_1)
elif helper_1[1] == 5:
win_5.append(helper_1)
elif helper_1[1] == 6:
win_6.append(helper_1)
elif helper_1[1] == 7:
win_7.append(helper_1)
elif helper_1[1] == 8:
win_8.append(helper_1)
elif helper_1[1] == 9:
win_9.append(helper_1)
elif helper_1[1] == 10:
win_10.append(helper_1)
v += 1
random.shuffle(win_0)
random.shuffle(win_1)
random.shuffle(win_2)
random.shuffle(win_3)
random.shuffle(win_4)
random.shuffle(win_5)
random.shuffle(win_6)
random.shuffle(win_7)
random.shuffle(win_8)
random.shuffle(win_9)
random.shuffle(win_10)
while len(helper) > 0:
helper.pop()
helper.append(win_10)
helper.append(win_9)
helper.append(win_8)
helper.append(win_7)
helper.append(win_6)
helper.append(win_5)
helper.append(win_4)
helper.append(win_3)
helper.append(win_2)
helper.append(win_1)
helper.append(win_0)
def even():
b = 0
while b <= (number_of_com - 2):
helper_1 = helper[b]
b += 1
helper_2 = helper[b]
print ("Player " + str(helper_1[0]) + " is vs player " +str(helper_2[0]) + ".")
b += 1
b = 0
while b <= (number_of_com - 2):
helper_1 = helper[b]
b += 1
helper_2 = helper[b]
print("In the match between player " + str(helper_1[0]) + " and player " +str(helper_2[0]) + " who won?")
a = int(input("Enter 1 if player " + str(helper_1[0]) + " won or 2 if player " + str(helper_2[0]) + " won."))
if a == 1 or a == 2:
if a == 1:
helper_1[1] += 1
helper_2[2] += 1
b -= 1
helper[b] = helper_1
b += 1
helper[b] = helper_2
else:
helper_1[2] += 1
helper_2[1] += 1
b -= 1
helper[b] = helper_1
b += 1
helper[b] = helper_2
else:
print("Enter a correct number.")
b -= 1
continue
b += 1
random.shuffle(helper)
v = 0
while v < number_of_com:
helper_1 = helper[v]
if helper_1[1] == 0:
win_0.append(helper_1)
elif helper_1[1] == 1:
win_1.append(helper_1)
elif helper_1[1] == 2:
win_2.append(helper_1)
elif helper_1[1] == 3:
win_3.append(helper_1)
elif helper_1[1] == 4:
win_4.append(helper_1)
elif helper_1[1] == 5:
win_5.append(helper_1)
elif helper_1[1] == 6:
win_6.append(helper_1)
elif helper_1[1] == 7:
win_7.append(helper_1)
elif helper_1[1] == 8:
win_8.append(helper_1)
elif helper_1[1] == 9:
win_9.append(helper_1)
elif helper_1[1] == 10:
win_10.append(helper_1)
v += 1
random.shuffle(win_0)
random.shuffle(win_1)
random.shuffle(win_2)
random.shuffle(win_3)
random.shuffle(win_4)
random.shuffle(win_5)
random.shuffle(win_6)
random.shuffle(win_7)
random.shuffle(win_8)
random.shuffle(win_9)
random.shuffle(win_10)
while len(helper) > 0:
helper.pop()
helper.append(win_10)
helper.append(win_9)
helper.append(win_8)
helper.append(win_7)
helper.append(win_6)
helper.append(win_5)
helper.append(win_4)
helper.append(win_3)
helper.append(win_2)
helper.append(win_1)
helper.append(win_0)
if number_of_com % 2 == 0:
c = 1
while c <= loop:
even()
c += 1
else:
c = 1
while c <= loop:
odd()
c += 1
答案 0 :(得分：29)
你不能重新调整字典。你可以做的是创建一个字典键的列表并随机 ，以便实现一个新的任意顺序来访问字典的内容：
>>> import random
>>> d = {1:2, 3:4, 5:6, 7:8, 9:10}
>>> d
{1: 2, 3: 4, 9: 10, 5: 6, 7: 8}
>>> keys = list(d.keys()) # Python 3; use keys = d.keys() in Python 2
>>> random.shuffle(keys)
>>> [(key, d[key]) for key in keys]
[(1, 2), (5, 6), (7, 8), (9, 10), (3, 4)]
>>> random.shuffle(keys)
>>> [(key, d[key]) for key in keys]
[(9, 10), (3, 4), (1, 2), (7, 8), (5, 6)]
>>> random.shuffle(keys)
>>> [(key, d[key]) for key in keys]
[(1, 2), (7, 8), (3, 4), (5, 6), (9, 10)]
答案 1 :(得分：3)
嗯，我认为你也可以做得更简单，没有lambdas等。
from random import shuffle
from collections import OrderedDict
a = {num-97:chr(num) for num in range(97, 107)}
# a = {0: 'a', 1: 'b', 2: 'c', 3: 'd', 4: 'e', 5: 'f', 6: 'g', 7: 'h', 8: 'i', 9: 'j'}
b = list(a.items())
shuffle(b)
a = OrderedDict(b) #Or just stay with b
# a = OrderedDict([(1, 'b'), (6, 'g'), (4, 'e'), (3, 'd'), (5, 'f'), (8, 'i'), (2, 'c'), (7, 'h'), (9, 'j'), (0, 'a')])
# b = [(1, 'b'), (6, 'g'), (4, 'e'), (3, 'd'), (5, 'f'), (8, 'i'), (2, 'c'), (7, 'h'), (9, 'j'), (0, 'a')]
我认为使用shuffle会使代码更清晰，然后使用随机键排序。
对于洗牌，只会产生类似：
keys = list(a.keys())
shuffle(keys)
OrderedDict(zip(keys, a.values()))
# OrderedDict([(3, 'a'), (1, 'b'), (9, 'c'), (4, 'd'), (6, 'e'), (8, 'f'), (0, 'g'), (2, 'h'), (5, 'i'), (7, 'j')])
答案 2 :(得分：1)
您无法订购内置dict，但在collections模块中有OrderedDict：
>>> from collections import OrderedDict
>>> from random import random
>>> od = OrderedDict(a=1, b=2, c=3, d=4)
>>> # sorts a list by whatever the key-callable returns => its randomly sorted
>>> shuffled_key_value_list = sorted(od.items(), key=lambda x: random())
>>> shuffled_key_value_list # (this might also do it)
[('d', 4), ('c', 3), ('a', 1), ('b', 2)]
>>> OrderedDict(shuffled_key_value_list)
OrderedDict([('d', 4), ('c', 3), ('a', 1), ('b', 2)])
答案 3 :(得分：0)
随机为值分配键：
from random import shuffle
x = dict(a=1, b=2, c=3, d=4)
# py2.7
values = x.values()
# py3.*
values = list( x.values() )
# It does not make any difference, whether values or keys are shuffled
# but it could lead to wrong conclusions to shuffle the keys.
shuffle(values)
y = dict(zip(x.keys(), values))
# py2.7
print y
# py3.*
print(y)
输出
{'a': 1, 'c': 4, 'b': 2, 'd': 3}
答案 4 :(得分：0)
我看到那些家伙扭曲了这个简单的问题（如果我得到它）。为了改组字典的内容，我们可以说
a={'a':1,'b':2,'c':3}
我们可以通过三个简单的步骤来完成：
列出给定字典的项目
a1 = list（a.items（））
Out [1]：[（'a'，1），（'b'，2），（'c'，3）]
改组项目列表
numpy.random.shuffle（a1）的
Out [2]：[（'b'，2），（'c'，3），（'a'，1）]
获取随机字典
a = dict（a1）
Out [3]：{'b'：2，'c'：3，'a'：1}
答案 5 :(得分：0)
如果您使用的是正式订购字典的Python 3.7，则可以将字典项转换为元组列表以进行改组，然后再使用dict()构造函数将其转换为字典：
import random
d = {'a':1, 'b':2, 'c':3, 'd':4}
l = list(d.items())
random.shuffle(l)
d = dict(l)
答案 6 :(得分：0)
随机设置字典的简单思路是使用集。即使你不 需要随机图书馆。
d = {'a':'1','b':'2','c':'3','d':'4'}
d_set = list(set(d))
d = {i:d[i] for i in d_set}