Question

在你问之前，我确实看过其他答案和问题，他们似乎都是一样的，是的，我确实添加了但仍然没有。好的，所以我有一个带菜单的程序，在菜单选项中它会在“：”冒号处出现语法错误，请帮助我尝试了所有内容。这是代码：

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = (input("What would you like to search?: ")
            if menu == '1':
                print("You chose Class")
                list = ['Assault', 'Engineer', 'Support', 'Recon']
                from random import choice
                print(choice(list))

            elif menu == '2'
                print("nice")

错误= 语法错误然后突出显示红色的“：”。

Answer 1

您错过了input函数的右括号，您完全不需要它。

menu = input("What would you like to search?: ")

完整的固定代码：

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = input("What would you like to search?: ")
    if menu == '1':
        print("You chose Class")
        list = ['Assault', 'Engineer', 'Support', 'Recon']
        from random import choice
        print(choice(list))

    elif menu == '2':
        print("nice")

Answer 2

input()在开头有一个不必要的禁忌。
if语句错误缩进。
elif没有:
必须在开始时进口。

更正代码

from random import choice
def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = input("What would you like to search?: ")
    if menu == '1':
        print("You chose Class")
        list = ['Assault', 'Engineer', 'Support', 'Recon']
        print(choice(list))

    elif menu == '2':
        print("nice")

简单IF上的语法错误。

2 个答案: