Question

下面是我的UI和表格。我想在gridview中插入一个孩子的图像，它也将保存在数据库中。请帮助我实现这一点。

表格中图片的数据类型为 varchar（MAX）。

这是我到目前为止所做的。

（C＃代码）

  using System;
  using System.Collections.Generic;
  using System.Linq;
  using System.Web;
  using System.Web.UI;
  using System.Web.UI.WebControls;
  using System.Data;
  using System.Data.SqlClient;
  using System.IO;
  using System.Configuration;

  namespace MyProject
  {
public partial class managechild : System.Web.UI.Page
{

SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["lolConnectionString1"].ConnectionString);
protected void Page_Load(object sender, EventArgs e)
{

    if (!IsPostBack)
    {           
        BindGrid();
    }
} 
protected void BindGrid()
{
    string session = System.Web.HttpContext.Current.User.Identity.Name;
    Response.Cookies["uname"].Value = session;

    DataSet ds = new DataSet();
    conn.Open();
    string cmdstr = "SELECT * from child c join parent p on c.ParentId = p.ParentId join login l on l.Username = p.UserId where l.Username ='" + session + "'";
    SqlCommand cmd = new SqlCommand(cmdstr, conn);
    SqlDataAdapter adp = new SqlDataAdapter(cmd);
    adp.Fill(ds);
    gvUpload.DataSource = ds;
    gvUpload.DataBind();
    conn.Close();
}

protected void btnUpload_OnClick(object sender, EventArgs e)
{
        TextBox txtName = (TextBox)gvUpload.SelectedRow.FindControl("ChildName");
        FileUpload fuploadFile = (FileUpload)gvUpload.SelectedRow.FindControl("fUpload");
        Button btnUpload = (Button)gvUpload.SelectedRow.FindControl("btnUpload");

if (fuploadFile.HasFile)
{               
    string fileName = fuploadFile.FileName;
    string exten = Path.GetExtension(fileName); 
    //here we have to restrict file type            
    exten = exten.ToLower();
    string[] acceptedFileTypes = new string[4];            
    acceptedFileTypes[0] = ".jpg";
    acceptedFileTypes[1] = ".jpeg";
    acceptedFileTypes[2] = ".gif";
    acceptedFileTypes[3] = ".png";                               
    bool acceptFile = false;              
    for (int i = 0; i <= 3; i++)
    {
        if (exten == acceptedFileTypes[i])
        {                     
            acceptFile = true;
        }
    } 
    if (!acceptFile)
    {
        lblMsg.Text = "The file you are trying to upload is not a permitted file type!";
    }
    else
    {
        //upload the file onto the server                   
        fuploadFile.SaveAs(Server.MapPath("~/images/child/"+fileName));

        conn.Open();
        string cmdstr = "insert into Child (Image) values (@photo)";
        SqlCommand cmd = new SqlCommand(cmdstr, conn);
        cmd.Parameters.AddWithValue("@photo", "images/child/"+fileName);
        cmd.ExecuteNonQuery();
        conn.Close();
        BindGrid();
    }
}       
} 

}
}

enter image description here

UI代码（asp.net）

    <asp:GridView ID="gvUpload" runat="server" AutoGenerateColumns="False" 
                ShowFooter="True" CellPadding="4" ForeColor="#333333" GridLines="None" 
                style="margin-left: 128px">
            <AlternatingRowStyle BackColor="White" ForeColor="#284775" />
   <Columns>
    <asp:TemplateField HeaderText="Child Name">
        <ItemTemplate>
            <asp:Label ID="lblName" runat="server" Text='<%#DataBinder.
                              Eval(Container.DataItem, "ChildName") %>'></asp:Label>
    </ItemTemplate>
    </asp:TemplateField> 
    <asp:TemplateField HeaderText="Image">
    <ItemTemplate>
         <asp:Image ID="imgPhoto" runat="server" Width="100px" Height="120px"
                 ImageUrl='<%#DataBinder.Eval(Container.DataItem, "Image") %>' />
    </ItemTemplate>
    <ItemTemplate>
         <asp:FileUpload ID="fUpload" runat="server" />
    </ItemTemplate>
    </asp:TemplateField>
    <asp:TemplateField>
        <ItemTemplate>
            <asp:Button ID="btnUpload" runat="server" Text="Upload"
                                           OnClick="btnUpload_OnClick" />
        </ItemTemplate>
    </asp:TemplateField>
    </Columns>
            <EditRowStyle BackColor="#999999" />
            <FooterStyle BackColor="#5D7B9D" Font-Bold="True" ForeColor="White" />
            <HeaderStyle BackColor="#5D7B9D" Font-Bold="True" ForeColor="White" />
            <PagerStyle BackColor="#284775" ForeColor="White" HorizontalAlign="Center" />
            <RowStyle BackColor="#F7F6F3" ForeColor="#333333" />
            <SelectedRowStyle BackColor="#E2DED6" Font-Bold="True" ForeColor="#333333" />
            <SortedAscendingCellStyle BackColor="#E9E7E2" />
            <SortedAscendingHeaderStyle BackColor="#506C8C" />
            <SortedDescendingCellStyle BackColor="#FFFDF8" />
            <SortedDescendingHeaderStyle BackColor="#6F8DAE" />
    </asp:GridView>

Answer 1

在SO Pls上发帖时，请确保在向其他人提供完整解决方案之前至少展示一些自己解决问题的尝试。

一种方法是将数据库中的图像保存为二进制数据，在这种情况下，您需要将varbinary列添加到表中。

另一种方法是仅保存图像的路径并将图像保存在服务器上的某个文件夹中。

如果你没有很多图像，我建议你选择第二种解决方案，因为它更容易实现。只需查看如何上传图像文件，您就会走在正确的轨道上。

从asp.net gridview将图像插入数据库

1 个答案: