我正在尝试迭代并按id搜索,并通过控制器中的$ resource从下面显示的类型的JSON对象返回与id对应的其他值。在这种情况下,我不明白我错在哪里?请帮忙!
这是控制器
appSettings.controller('applistController', ['$scope', 'AppListService',
function($scope, AppListService){
// Have to iterate here to search for an id, how?
// The Above app.json file is returned by the ApplistService(not showing the factory here as it works already.)
$scope.allapps = AppListService.listAllApps().get();
// console.log($scope.allapps.data) returns undefined as so does console.log($scope.allapps.length).
// Where am I wrong?
}
]);
JSON的类型为:
{"data":[
{
"id":"files_trashbin",
"name": "TrashBin",
"licence":"AGPL",
"require":"4.9",
"shipped": "true",
"active":true
},
{
"id":"files_external",
"name": "External Storage",
"licence":"AGPL",
"require":"4.93",
"shipped":"true",
"active":true
}
],
"status":"success"
}
答案 0 :(得分:2)
我认为AppListService.listAllApps().get();
会返回承诺。听起来像是在获得实际数据之前尝试打印。
我会使用以下方法:
var appSettings = angular.module('myModule', ['ngResource']);
appSettings.controller('applistController', ['$scope', 'AppListService',
function($scope, AppListService){
AppListService.listAllApps()
.then(function (result) {
$scope.allapp = result;
}, function (result) {
alert("Error: No data returned");
});
}]);
appSettings.factory('AppListService', ['$resource','$q', function($resource, $q) {
var data = $resource('somepath',
{},
{ query: {method:'GET', params:{}}}
);
var factory = {
listAllApps: function () {
var deferred = $q.defer();
deferred.resolve(data);
return deferred.promise;
}
}
return factory;
}]);
答案 1 :(得分:1)
以下代码显示了基于json的id值的提取。
var json = '{"data":[{"id":"files_trashbin","name":"TrashBin","licence":"AGPL","require":"4.9","shipped":"true","active":true},{"id":"files_external","name":"External Storage","licence":"AGPL","require":"4.93","shipped":"true","active":true}],"status":"success"}';
$scope.allapps = JSON.parse(json);
$scope.ids = new Array();
var sourceData = $scope.allapps["data"];
for (var i=0; i<sourceData.length; i++) {
$scope.ids.push(sourceData[i].id);
}
这是一个与Angular集成的an example of this extraction的jsFiddle。
此代码假定您的服务返回的JSON与您显示的内容相同。请注意 - 您的JSON文本中最初有一些额外的和丢失的逗号(我后来修复了这些逗号),这可能也导致了您看到的错误。