Question

我正在使用此

获取字符串的文本大小

textSize = [[tempDict valueForKeyPath:@"caption.text"] sizeWithFont:[UIFont systemFontOfSize:12] constrainedToSize:CGSizeMake(280, CGFLOAT_MAX) lineBreakMode: NSLineBreakByWordWrapping];

我唯一的问题是，如果字符串只包含表情符号，我的应用程序崩溃了。有没有一种简单的方法来检查表情符号，或者我是否必须创建一个包含所有可能的表情符号的数组，然后使用它来检查它们？

错误：

-[NSNull sizeWithFont:constrainedToSize:lineBreakMode:]: unrecognized selector sent to instance 0x3aa88a60


if ([tempDict valueForKeyPath:@"caption.text"]){
            NSLog(@"%@", [tempDict valueForKeyPath:@"caption"]);
            //Measure the message label box height
            textSize = [[tempDict valueForKeyPath:@"caption.text"] sizeWithFont:[UIFont systemFontOfSize:12] constrainedToSize:CGSizeMake(280, CGFLOAT_MAX) lineBreakMode: NSLineBreakByWordWrapping];
            int height = 320 + 20 + textSize.height;
            [cellHeight addObject:[NSNumber numberWithInt:height]];
}

Answer 1

试试这段代码：

- (BOOL)stringContainsEmoji:(NSString *)string {
    __block BOOL returnValue = NO;
    [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
     ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {

         const unichar hs = [substring characterAtIndex:0];
         // surrogate pair
         if (0xd800 <= hs && hs <= 0xdbff) {
             if (substring.length > 1) {
                 const unichar ls = [substring characterAtIndex:1];
                 const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
                 if (0x1d000 <= uc && uc <= 0x1f77f) {
                     returnValue = YES;
                 }
             }
         } else if (substring.length > 1) {
             const unichar ls = [substring characterAtIndex:1];
             if (ls == 0x20e3) {
                 returnValue = YES;
             }

         } else {
             // non surrogate
             if (0x2100 <= hs && hs <= 0x27ff) {
                 returnValue = YES;
             } else if (0x2B05 <= hs && hs <= 0x2b07) {
                 returnValue = YES;
             } else if (0x2934 <= hs && hs <= 0x2935) {
                 returnValue = YES;
             } else if (0x3297 <= hs && hs <= 0x3299) {
                 returnValue = YES;
             } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {
                 returnValue = YES;
             }
         }
     }];

    return returnValue;
}

Answer 2

@Simha.IC答案很棒。

然而，它不适用于新的iOS 9.1 emojis＆＃39;。

Simha.IC片段未检测到这些：
☂️✝️✡️☯️

所以为了解决这个问题，我稍微调整了一下代码并用它创建了一个类别：

- (BOOL)emo_containsEmoji
{
    __block BOOL containsEmoji = NO;

    [self enumerateSubstringsInRange:NSMakeRange(0,
                                                 [self length])
                             options:NSStringEnumerationByComposedCharacterSequences
                          usingBlock:^(NSString *substring,
                                       NSRange substringRange,
                                       NSRange enclosingRange,
                                       BOOL *stop)
     {
         const unichar hs = [substring characterAtIndex:0];
         // surrogate pair
         if (0xd800 <= hs &&
             hs <= 0xdbff)
         {
             if (substring.length > 1)
             {
                 const unichar ls = [substring characterAtIndex:1];
                 const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
                 if (0x1d000 <= uc &&
                     uc <= 0x1f9c0)
                 {
                     containsEmoji = YES;
                 }
             }
         }
         else if (substring.length > 1)
         {
             const unichar ls = [substring characterAtIndex:1];
             if (ls == 0x20e3 ||
                 ls == 0xfe0f ||
                 ls == 0xd83c)
             {
                 containsEmoji = YES;
             }
         }
         else
         {
             // non surrogate
             if (0x2100 <= hs &&
                 hs <= 0x27ff)
             {
                 containsEmoji = YES;
             }
             else if (0x2B05 <= hs &&
                      hs <= 0x2b07)
             {
                 containsEmoji = YES;
             }
             else if (0x2934 <= hs &&
                      hs <= 0x2935)
             {
                 containsEmoji = YES;
             }
             else if (0x3297 <= hs &&
                      hs <= 0x3299)
             {
                 containsEmoji = YES;
             }
             else if (hs == 0xa9 ||
                      hs == 0xae ||
                      hs == 0x303d ||
                      hs == 0x3030 ||
                      hs == 0x2b55 ||
                      hs == 0x2b1c ||
                      hs == 0x2b1b ||
                      hs == 0x2b50)
             {
                 containsEmoji = YES;
             }
         }
     }];

    return containsEmoji;
}

我的类别可以计算：

如果字符串有emojis
表情符号的数量
每个表情符号的范围

I created a small project with the category as an example.

I also created a pod with the category也许你想尝试一下。

Answer 3

这就是我正在使用的：

func isAllEmoji(aString: String) -> Bool {
    for scalar in aString.unicodeScalars {
        switch scalar.value {
        case 0x1F600...0x1F64F, // Emoticons
        0x1F300...0x1F5FF, // Misc Symbols and Pictographs
        0x1F680...0x1F6FF, // Transport and Map
        0x2600...0x26FF,   // Misc symbols
        0x2700...0x27BF,   // Dingbats
        0xFE00...0xFE0F,   // Variation Selectors
        0x0030...0x0039,
        0x00A9...0x00AE,
        0x203C...0x2049,
        0x2122...0x3299,
        0x1F004...0x1F251,
        0x1F910...0x1F990:
            break
        default:
            return false
        }
    }
    return true
}

我用this遗漏了一些表情符号范围，然后使用this表情符号数组通过迭代找到缺少的样本...没有经过深度测试。

Answer 4

您可以使用此新框架

https://github.com/woxtu/NSString-RemoveEmoji

用法：

 <TabHost xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@android:id/tabhost"
    android:layout_width="match_parent"
   android:layout_height="match_parent" >


   <LinearLayout
        android:id="@+id/LinearLayout01"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:orientation="vertical" >

        <TabWidget
            android:id="@android:id/tabs"
            android:layout_width="fill_parent"
            android:layout_height="wrap_content" />

        <FrameLayout
            android:id="@android:id/tabcontent"
            android:layout_width="fill_parent"
            android:layout_height="fill_parent" >
        </FrameLayout>
    </LinearLayout>

  </TabHost>

Answer 5

如果有任何字符超过0x00ff，则可能会出现此问题。换句话说，除了表情符号之外，还有许多Unicode字符可能需要考虑。为了查看是否有任何Unicode字符（超出扩展ASCII的边界），请使用以下内容。

extension String {

  var containsUnicodeCharacters: Bool {
    for scalar in unicodeScalars {
      if scalar.value > 0x00FF {
        return true
      }
    }
    return false
  }

}

Answer 6

对此进行回复为时已晚，但可能会对某人有所帮助。

- (BOOL)stringContainsEmoji:(NSString *)string {

    __block BOOL returnValue = NO;

    [string enumerateSubstringsInRange:NSMakeRange(0, string.length)
                               options:NSStringEnumerationByComposedCharacterSequences
                            usingBlock:^(NSString* substring, NSRange substringRange, NSRange enclosingRange, BOOL* stop)
     {
         const unichar hs = [substring characterAtIndex:0];
         const unichar ls = substring.length > 1 ? [substring characterAtIndex:1] : 0;

#define IS_IN(val, min, max) (((val) >= (min)) && ((val) <= (max)))

         if(IS_IN(hs, 0xD800, 0xDBFF))
         {
             if(substring.length > 1)
             {
                 const int uc = ((hs - 0xD800) * 0x400) + (ls - 0xDC00) + 0x10000;

                 // Musical: [U+1D000, U+1D24F]
                 // Enclosed Alphanumeric Supplement: [U+1F100, U+1F1FF]
                 // Enclosed Ideographic Supplement: [U+1F200, U+1F2FF]
                 // Miscellaneous Symbols and Pictographs: [U+1F300, U+1F5FF]
                 // Supplemental Symbols and Pictographs: [U+1F900, U+1F9FF]
                 // Emoticons: [U+1F600, U+1F64F]
                 // Transport and Map Symbols: [U+1F680, U+1F6FF]
                 if(IS_IN(uc, 0x1D000, 0x1F9FF))
                     returnValue = YES;
             }
         }
         else if(substring.length > 1 && ls == 0x20E3)
         {
             // emojis for numbers: number + modifier ls = U+20E3
             returnValue = YES;
         }
         else
         {
             if(        // Latin-1 Supplement
                hs == 0x00A9 || hs == 0x00AE
                // General Punctuation
                ||  hs == 0x203C || hs == 0x2049
                // Letterlike Symbols
                ||  hs == 0x2122 || hs == 0x2139
                // Arrows
                ||  IS_IN(hs, 0x2194, 0x2199) || IS_IN(hs, 0x21A9, 0x21AA)
                // Miscellaneous Technical
                ||  IS_IN(hs, 0x231A, 0x231B) || IS_IN(hs, 0x23E9, 0x23F3) || IS_IN(hs, 0x23F8, 0x23FA) || hs == 0x2328 || hs == 0x23CF
                // Geometric Shapes
                ||  IS_IN(hs, 0x25AA, 0x25AB) || IS_IN(hs, 0x25FB, 0x25FE) || hs == 0x25B6 || hs == 0x25C0
                // Miscellaneous Symbols
                ||  IS_IN(hs, 0x2600, 0x2604) || IS_IN(hs, 0x2614, 0x2615) || IS_IN(hs, 0x2622, 0x2623) || IS_IN(hs, 0x262E, 0x262F)
                ||  IS_IN(hs, 0x2638, 0x263A) || IS_IN(hs, 0x2648, 0x2653) || IS_IN(hs, 0x2665, 0x2666) || IS_IN(hs, 0x2692, 0x2694)
                ||  IS_IN(hs, 0x2696, 0x2697) || IS_IN(hs, 0x269B, 0x269C) || IS_IN(hs, 0x26A0, 0x26A1) || IS_IN(hs, 0x26AA, 0x26AB)
                ||  IS_IN(hs, 0x26B0, 0x26B1) || IS_IN(hs, 0x26BD, 0x26BE) || IS_IN(hs, 0x26C4, 0x26C5) || IS_IN(hs, 0x26CE, 0x26CF)
                ||  IS_IN(hs, 0x26D3, 0x26D4) || IS_IN(hs, 0x26D3, 0x26D4) || IS_IN(hs, 0x26E9, 0x26EA) || IS_IN(hs, 0x26F0, 0x26F5)
                ||  IS_IN(hs, 0x26F7, 0x26FA)
                ||  hs == 0x260E || hs == 0x2611 || hs == 0x2618 || hs == 0x261D || hs == 0x2620 || hs == 0x2626 || hs == 0x262A
                ||  hs == 0x2660 || hs == 0x2663 || hs == 0x2668 || hs == 0x267B || hs == 0x267F || hs == 0x2699 || hs == 0x26C8
                ||  hs == 0x26D1 || hs == 0x26FD
                // Dingbats
                ||  IS_IN(hs, 0x2708, 0x270D) || IS_IN(hs, 0x2733, 0x2734) || IS_IN(hs, 0x2753, 0x2755)
                ||  IS_IN(hs, 0x2763, 0x2764) || IS_IN(hs, 0x2795, 0x2797)
                ||  hs == 0x2702 || hs == 0x2705 || hs == 0x270F || hs == 0x2712 || hs == 0x2714 || hs == 0x2716 || hs == 0x271D
                ||  hs == 0x2721 || hs == 0x2728 || hs == 0x2744 || hs == 0x2747 || hs == 0x274C || hs == 0x274E || hs == 0x2757
                ||  hs == 0x27A1 || hs == 0x27B0 || hs == 0x27BF
                // CJK Symbols and Punctuation
                ||  hs == 0x3030 || hs == 0x303D
                // Enclosed CJK Letters and Months
                ||  hs == 0x3297 || hs == 0x3299
                // Supplemental Arrows-B
                ||  IS_IN(hs, 0x2934, 0x2935)
                // Miscellaneous Symbols and Arrows
                ||  IS_IN(hs, 0x2B05, 0x2B07) || IS_IN(hs, 0x2B1B, 0x2B1C) || hs == 0x2B50 || hs == 0x2B55
                )
             {
                 returnValue = YES;
             }
         }

#undef IS_IN
     }];

    return returnValue;
}

Answer 7

请参阅此答案How to get NSString size when NSString includes emojis?

如果您只有表情符号，则不应使用sizeWithFont。使用标签或其他东西。

NSString不适用于Emojis，只适用于文本。如果您有表情符号，则应使用[label sizeToFit]或[label sizeThatFits:]

此外，您可以使用此代码：

 id text = [tempDict valueForKeyPath:@"caption.text"]

 if (![text isKindOfClass:[NSNull class]]) {
 ...
 }

因为，你从字典中获得NSNull，但它不等于nil，并且你的条件有效。

Answer 8

人们一次又一次地使用valueForKeyPath而不是objectForKey。他们都无法解释原因。阅读文档。如果在阅读之后您可以解释为什么使用valueForKeyPath（和＃34;我从某处复制了它＆＃34;不是解释），将其更改为objectForKey。

你遇到的问题根本与Emojis无关。任何在字符串中检测Emojis的尝试都将失败 - 原因很简单，你首先没有字符串，你有[NSNull null]。可以通过使用objectForKey来解决这个问题 - 你可能会得到nil而不是更宽容的行为。或者你仍然得到[NSNull null]。

找出你获得[NSNull null]的原因。有人把它放在那里。如果你不能阻止它在那里，那么你需要处理它。

Answer 9

现在有了 iOS 10 的新版本，对于以下表情符号，它不起作用：

Emojis

以下代码片段针对iOS 9和iOS 10进行了尝试和测试：

extension String {

    var containsEmoji: Bool {
        for scalar in unicodeScalars {
            switch scalar.value {
            case 0x1F600...0x1F64F, // Emoticons
            0x1F300...0x1F5FF, // Misc Symbols and Pictographs
            0x1F680...0x1F6FF, // Transport and Map
            0x2600...0x26FF,   // Misc symbols
            0x2700...0x27BF,   // Dingbats
            0xFE00...0xFE0F,   // Variation Selectors
            0x1F910...0x1F918, // New Emoticons
            0x1F1E6...0x1F1FF, // Flags
            0x1F980...0x1F984,
            0x1F191...0x1F19A,
            0x1F201...0x1F202,
            0x1F232...0x1F23A,
            0x1F250...0x1F251,
            0x23E9...0x23F3,
            0x23F8...0x23FA,
            0x1F170...0x1F171,
            0x1F17E,
            0xA9,
            0xAE,
            0x2122,
            0x2328,
            0x3030,
            0x1F0CF,
            0x1F18E,
            0x1F9C0:
                return true
            default:
                continue
            }
        }
        return false
    }
}

如上所述，在您的应用中创建一个String扩展名。

可以像这样使用：

if string.containsEmoji {
    // Do operations here
}

Answer 10

一种简单的Swift解决方案，用于检查unicode中的每个标量。标量位于CharacterSet.symbols集中。

extension String {
    var containsEmoji: Bool {
        for scalar in unicodeScalars {
            if CharacterSet.symbols.contains(scalar) {
                return true
            }
        }

        return false
    }
}

但是我发现像ℹ️这样的emoji 1.0项目没有被归类为emoji。因此，我创建了此检查器：

extension Unicode.Scalar {
    extension Unicode.Scalar {
        var isEmojiMiscSymbol: Bool {
            switch self.value {
            case 0x2030...0x329F:   // Misc symbols
                return true
            default:
                return false
            }
        }
    }
}

这是可以检测ℹ️的检查器：

extension String {
    var containsEmoji: Bool {
        for scalar in unicodeScalars {
            if CharacterSet.symbols.contains(scalar) {
                return true
            } else if scalar.isEmojiMiscSymbol {
                return true
            }
        }

        return false
    }
}

检查字符串中是否包含表情符号

10 个答案: