Question

我收到以下错误：

Fatal error: Call to undefined method database::connect() in
/Applications/XAMPP/xamppfiles/htdocs/proyectoFinal/core/class.ManageDatabase.php 
on line 8

有谁知道发生了什么事？方法是在类中定义的。这部分似乎是问题所在：$this->link = $conn->connect();

课程如下：

<?php 

include_once('../config.php');

    class database{
        protected $db_conn;
        public $db_name = DB_NAME;
        public $db_host = DB_HOST;
        public $db_pass = DB_PASS;
        public $db_user = DB_USER;  
    }

    function connect(){
        try{
            $this->$db_conn = new PDO("mysql:host = 
                    $this->db_host;dbname=$this->db_name",
                    $this->db_user, $this->db_pass);
            return $this->db_conn;  
        }
        catch(PDOException $e)
        {
        return $e->getMessage();
        }
    }
?>

以下方法调用的方法：

<?php
    include_once('../core/class.ManageDatabase.php');
    $init = new ManageDatabase;

    $table_name = 'persona';
    $data = $init->getData($table_name);

    print_r($data);
?>

Answer 1

class database{
    protected $db_conn;
    public $db_name = DB_NAME;
    public $db_host = DB_HOST;
    public $db_pass = DB_PASS;
    public $db_user = DB_USER;  
} // <-- end of class database

它确实没有任何方法。我相信如果你希望函数}成为它的一个方法，你应该移动这个connect()，并且只在函数之后放置它。

Answer 2

你关闭了课程，所以： function connect(){ /* */ }

超出了对象范围。

class database{
        protected $db_conn;
        public $db_name = DB_NAME;
        public $db_host = DB_HOST;
        public $db_pass = DB_PASS;
        public $db_user = DB_USER;  
    } // Remove this and add it at the end of your class definition

话虽如此，database->connect();将不是一个定义的方法。相反：

$Var = connect();

将与当前设置一起使用

PHP无法识别类中定义的方法

2 个答案: