public class Tester
{
// instance variables - replace the example below with your own
Scanner operation = new Scanner(System.in);
IntegerCalc calc = new IntegerCalc();
public Tester()
{
char choice;
String value;
char again;
}
public void test()
{
char again = operation.next().charAt(0);
do{
System.out.println("Please pick one of the following operations: 1. Addition 2. Subtraction" +
"3. Multiplication 4.Division 5. Modulo 6. Square 7.Square Root");
int num = operation.nextInt();
int ch;
ch = operation.nextInt();
String choice;
choice = operation.next();
switch (ch){
case 1: calc.addition(num,num);
break;
case 2: calc.subtraction(num, num);
break;
case 3: calc.multiplication(num, num);
break;
case 4: calc.division(num, num);
break;
case 5: calc.modulo(num, num);
break;
case 6:calc.square(num);
break;
case 7: calc.squareRoot(num);
break;
default: System.out.println("Please enter a valid choice number.");
}
System.out.println("Type x to exit");
}while(again != 'x' && again != 'X');
{
System.out.println("Thank you for using my program!");
}
//这段代码的问题在于它甚至没有提示用户输入任何数据,它似乎只是陷入循环并且什么都不做。任何人都知道我能做些什么才能让它发挥作用?
答案 0 :(得分:2)
您在char again = operation.next().charAt(0);
循环之外有do/while
,因此如果again
满足while
条件,您将获得无限循环。
答案 1 :(得分:0)
您需要接受来自用户的角色
again = operation.next().charAt(0);
在此声明之后
System.out.println("Type x to exit");
答案 2 :(得分:0)
System.out.println("Type x to exit");
char again = operation.next().charAt(0);
这应该有效