Question

我正在尝试删除Amazon Glacier中的存档。我是通过PHP和PHP SDK2来做的。我有一点问题..我已经找到了获得ArchiveID的工作：

$this->client->initiateJob(array(
     'accountId' => '-',
     'vaultName' => $aValutName,
     'Type' => "inventory-retrieval")
);

几个小时后，我可以看到工作已经完成，所以我正在尝试使用它的ID获取工作：

   $res = $this->client->getJobOutput(array(
        'accountId' => '-',
        'vaultName' => $aValutName,
        'jobId' => $aJobID,
    ));

作为一种回应，我得到了这样的东西：

Guzzle\Service\Resource\Model Object
(
    [structure:protected] => 
    [data:protected] => Array
        (
            [body] => Guzzle\Http\EntityBody Object
                (
                    [contentEncoding:protected] => 
                    [rewindFunction:protected] => 
                    [stream:protected] => Resource id #152
                    [size:protected] => 
                    [cache:protected] => Array
                        (
                            [wrapper_type] => PHP
                            [stream_type] => TEMP
                            [mode] => w+b
                            [unread_bytes] => 0
                            [seekable] => 1
                            [uri] => php://temp
                            [is_local] => 1
                            [is_readable] => 1
                            [is_writable] => 1
                        )

                    [customData:protected] => Array
                        (
                            [default] => 1
                        )

                )

            [checksum] => 
            [status] => 200
            [contentRange] => 
            [acceptRanges] => bytes
            [contentType] => application/json
            [archiveDescription] => 
        )

)

enybody想知道为什么“archiveDescription”是空的吗？

也许有另一种获取ArchiveID的方法，所以我可以删除我的档案....

Thanx任何帮助; D

MK。

Answer 1

好的，解决方案太简单了......

public function getJobResult($aValutName, $aJobID) {
    $res = $this->client->getJobOutput(array(
        'accountId' => '-',
        'vaultName' => $aValutName,
        'jobId' => $aJobID,
    ));
    $body = EntityBody::factory($res['body']);
    $body->rewind();
    $inventory = stream_get_contents($body->getStream());
    $ArchiveList = json_decode($inventory,1)['ArchiveList'];
    $res = array();
    foreach($ArchiveList as $archive):
        $res[]=$archive['ArchiveId'];
    endforeach;


    return $res;
}

亚马逊冰川PHP和工作

1 个答案: