如何根据报表生成器中的条件添加空行

时间:2013-11-09 21:44:03

标签: sql report builder

我有具体的报告,我需要创建。我有两张桌子,一张有我公司的工作数据,另一张有在那里工作的人的数据。在工作表中有一个数据字段,其中包含有多少人可以从事某项工作的数据(工作名称和1,2或其他人数)。我需要报告,它将显示作业的名称,然后显示在该作业上工作的人员列表,但这是问题,如果人数较少,那么工作地点我需要为每个空工作地点添加空行。例如:

job name 1 = 3 places
job name 2 = 4 places

报告:

JOB NAME 1
---------------------- 
WORKING MAN NAME 1   
WORKING MAN NAME 2   
--- empty place ---  

JOB NAME 2
----------------------
WORKING MAN NAME 1   
WORKING MAN NAME 2   
--- empty place --- 
--- empty place --- 

我忘了提到我正在使用IBM系统Z上的DB2数据库以及用于构建我正在使用Visual Studio 10的报表。我的两个表是:

JOB:job_id,job_name,job_num_places

WORKER:worker_id,worker_name,job_id

我正在job_id上加入表格

1 个答案:

答案 0 :(得分:0)

WITH JobPositions AS (
    SELECT 'Job1' AS JobName, 3 AS Positions
  UNION ALL
    SELECT 'Job2', 4 AS Positions
)
,Workers AS (
    SELECT 'Worker1' AS WorkerName, 'Job1' AS JobName
  UNION ALL
    SELECT 'Worker2' AS WorkerName, 'Job1' AS JobName
  UNION ALL
    SELECT 'Worker3' AS WorkerName, 'Job2' AS JobName
)
-- Real query starts here.
-- Create a line for each position in each job
, JobPositionNumber AS (
    SELECT JobName, Positions, 1 AS PositionNumber
    FROM JobPositions
  UNION ALL
    SELECT JobName, Positions, PositionNumber + 1
    FROM JobPositionNumber
    WHERE PositionNumber < Positions
)
-- Number the workers from 1 and up per job
, WorkerPositionNumber AS (
    SELECT WorkerName
          ,JobName
          ,ROW_NUMBER() OVER (PARTITION BY JobName
                              ORDER BY WorkerName) AS PositionNumber
    FROM Workers
)
-- Now just join numbered jobs with numbered workers
SELECT JobPositionNumber.JobName
      ,CASE WHEN WorkerPositionNumber.WorkerName IS NULL 
            THEN '--- empty place ---' 
            ELSE WorkerName 
       END AS WorkerName 
FROM JobPositionNumber
     LEFT JOIN WorkerPositionNumber
         ON JobPositionNumber.JobName = WorkerPositionNumber.JobName
            AND JobPositionNumber.PositionNumber = WorkerPositionNumber.PositionNumber
ORDER BY JobPositionNumber.JobName
        ,JobPositionNumber.PositionNumber