Question

我创建了一个复杂的字典。

mainDict<mainKey, SubDict>
subDict<subKey, sub1Dict>
sub1Dict<sub1Key, sub2Dict>
sub2Dict<sub2Key, sub2Value>
.......

如何将其打印出来（基于vs2005＆amp; .net 2.0）

mainKey/subKey/sub1Key/sub2Key, sub2Value

我是否需要将mainDict转换为List并调用join（）？

谢谢。

Answer 1

StringBuilder sb = new StringBuilder();
foreach (KeyValuePair<mainKey, SubDict> pair1 in mainDict)
foreach (KeyValuePair<subKey, sub1Dict> pair2 in pair1.Value)
foreach (KeyValuePair<sub1Key, sub2Dict> pair3 in pair2.Value)
foreach (KeyValuePair<sub2Key, sub2Value> pair4 in pair3.Value)
{
    sb.AppendFormat("{0}/{1}/{2}/{3}, {4}", 
        pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair4.Value);
}

更新：

StringBuilder sb = new StringBuilder();
foreach (KeyValuePair<string, object> pair1 in mainDict)
foreach (KeyValuePair<string, object> pair2 in (Dictionary<string, object>)pair1.Value)
foreach (KeyValuePair<string, object> pair3 in (Dictionary<string, object>)pair2.Value)
foreach (KeyValuePair<string, object> pair4 in (Dictionary<string, object>)pair3.Value)
{
    sb.AppendFormat("{0}/{1}/{2}/{3}, {4}", 
        pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair4.Value);
}

Answer 2

看不到比嵌套循环更好的东西 - 遍历mainDict的键，然后是subDict的键，依此类推。然后，您可以将循环变量和最内层值呈现为字符串。

Answer 3

您可以使用LINQ：

var qry = from pair1 in mainDict
          from pair2 in pair1.Value
          from pair3 in pair2.Value
          from pair4 in pair3.Value
          select pair1.Key + "/" + pair2.Key + "/" + pair3.Key
                   + "/" + pair4.Key + ", " + pair4.Value;

foreach(var s in qry) Console.WriteLine(s);

Answer 4

我最后写了几分钟，试着在这里找到一个。我们走了：

        //---------------------------------------------------
        // Get a nested Dictionary, then...
        Console.WriteLine(DictionaryPrint(nestedDictionary));
        //---------------------------------------------------

        private static string DictionaryPrint(Dictionary<object,object> dictionary, string space = "")
        {
            string output = "";
            foreach(KeyValuePair<object,object> entry in dictionary)
            {
                output += space + entry.Key + ": ";
                if (entry.Value is Dictionary<object, object>)
                    output += "\n" + DictionaryPrint((Dictionary<object, object>)entry.Value, space + "  ");
                else if (entry.Value is List<object>)
                    output += "\n" + ListPrint((List<object>)entry.Value, space + "  ");
                else
                    output += entry.Value + "\n";
            }
            return output;
        }

        private static string ListPrint(List<object> list, string space = "")
        {
            string output = "";
            foreach (object entry in list)
            {
                if (entry is List<object>)
                    output += ListPrint((List<object>)entry, space + "  ");
                else if (entry is Dictionary<object, object>)
                    output += DictionaryPrint((Dictionary<object, object>)entry, space + "  ");
                else
                    output += entry + "\n";
            }
            return output;
        }

Answer 5

如果你碰巧使用JSON，你可能会比

更糟糕

JsonConvert.SerializeObject(yourDict, Formatting.Indented);

复杂字典打印

5 个答案: