所以我试图创建一个程序,在文件中搜索用户输入的单词。如果这是一场比赛,那就说'#34;找到它",如果找不到任何东西,它会说" COULDNT发现任何事情" (显然:p)。我不清楚如何扫描文件以查找用户选择的单词(通过scanf写入)。
这是我的(非功能性)代码。谢谢你的建议!
#include "stdafx.h"
#include <conio.h>
#include <iostream>
#include <string.h>
#include <string>
#define slovo 255
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
int i;
char secret[slovo];
int outexists,fileexists;
system("Color 02");
setlocale(LC_ALL, "");
FILE*out = fopen("additions.txt", "w+");
if (!out)
{
perror("additions.txt");
getchar();
return 1;
}
else
{
outexists = 1;
}
FILE*file = fopen("db.txt", "r");
if (!file)
{
perror("db.txt");
getchar();
return 1;
}
else
{
fileexists = 1;
}
char artist[slovo];
printf("Welcome, hit ENTER to start looking.\n");
getchar();
printf("Please enter for the word you wish to search for in our database !
\n ");
scanf("%s",&artist);
**/* THIS PART */** if (fileexists == 1 && outexists == 1)
{
while (fscanf(file, "%c", secret) != EOF){
{ if (!strncmp(secret, artist, sizeof(artist)))
{
printf("FOUND IT \n");
fclose(file);
}
else
{
printf("COULDNT FIND IT \n");
fclose(file);
}
}
}
}
printf("Which word do you wish to add ?\n");
scanf("%s", artist);
fprintf(out, "%s", artist);
printf("done! \n");
getchar();
fclose(file);
fclose(out);
getchar();
return 0;
}
答案 0 :(得分:0)
您可能需要转换模式%s
而不是%c
,后者只读取一个字符。前者读取一个字符串。
fscanf(file, "%s", secret)
修改强>
也看到了,
fclose(file);
只有一个if
+ else
后,您在while循环内的fscanf
和strncmp
中关闭文件。不要这样做,在wile循环终止后关闭文件。
另外,只需使用strcmp
代替strncmp
。
编辑2
因此,在复制粘贴你的“棘手”代码后,将我的控制台字体颜色变为绿色,我能够在文本文件中找到一个单词:
首先摆脱getchar();
!
printf("Welcome, hit ENTER to start looking.\n");
getchar();
我总是在打印Welcome, hit ENTER to start looking.
后输入要搜索的密钥,当按下输入时,由于getchar()
正在等待输入,所以没有读取任何内容。
第二
scanf("%s",&artist);
不正确,请使用
scanf("%s", artist);
相反,不需要传递地址,它已经是一个数组了!
printf("Welcome, hit ENTER to start looking.\n");
printf("Please enter for the word you wish to search for in our database !\n");
scanf("%s",artist);
if (fileexists == 1 && outexists == 1) {
char found = 0;
while (fscanf(file, "%s", secret) != EOF) {
if (!strcmp(secret, artist)) {
found = 1;
break;
}
}
fclose(file);
if(found) {
printf("FOUND IT \n");
} else {
printf("COULDNT FIND IT\n");
}
}
答案 1 :(得分:0)
嘿,我遇到了类似的问题,我尝试读取一个字符串(例如名称),并将其与用户输入或预先存储的字符串进行比较。但是过了一会儿,我意识到您必须做一些事情才能使其工作....
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int i;
int j;
int y;
char name_read[100];
char Testarr[100];
FILE *file = fopen("C:/Documents/readfile", "w+");//opened text file for writing
fprintf(file,"George|\n");// note i wrote the name "George" and put a '|' at the end
fclose(file);
char name_stored[100] = "George";//store the name we want to find
char str[100] = "";
FILE *ptr = fopen("C:/Documents/readfile","r");//open file for reading
printf("reading variables\n");
//loop everything below for reading multiple lines
fgets(name_read, 100, ptr);//read the name from the file
for(j = 0; j<= 100; j++){
if(name_read[j] == '|'){//check to see if we reached the marker '|'
for(i = 0; i<j; i++){
str[i] = name_read[i];//copy everything before the marker into str
}
}
}
printf("\n%s\n", str);
if(!strcmp(str, name_stored)){//compare the name we read from the file with the name stored
printf("match successful");
}
}
但是请注意,如果要读取多行名称,则可以实现所需的任何循环。