Question

我现在正在OpenCV中尝试BackgroundSubtractorMOG和BackgroundSubtractorMOG2，我想尝试jpg图像序列作为我的帧的来源

frame = imread("C:\images\001-capture.jpg");
    if(!frame.data){
    //error in opening the first image
    cerr << "Unable to open first image frame: " << fistFrameFilename << endl;
    //exit(EXIT_FAILURE);
}

另外，因为当我使用VideoCapture访问我的.avi视频片段时出现错误。

VideoCapture capture("C:\movie1.avi");
if(!capture.isOpened()){
    //error in opening the video input
    cerr << "Unable to open video file: " << videoFilename << endl;
    exit(EXIT_FAILURE);
}
//read input data. ESC or 'q' for quitting
while( (char)keyboard != 'q' && (char)keyboard != 27 ){
//read the current frame
if(!capture.read(frame)) {
  cerr << "Unable to read next frame." << endl;
  cerr << "Exiting..." << endl;
  exit(EXIT_FAILURE);
}

Answer 1

尝试使用VideoCapture捕获（“C：/movie1.avi”）; //使用单个“/”或双“\”！
如果图像编号正确，VideoCapture也可以读取图像序列：

VideoCapture capture（“C：/images/%3d-capture.jpg”）; //顺便说一句，与上面相同的斜线修改

Answer 2

@berak 所声明的VideoCapture方法是正确的;虽然我在使用它时不可避免地遇到了问题。在阅读连续图像时，我总是更喜欢下面所述的更直接的方法。它可以让您更好地控制遍历数据的方式，同时不限制速度。

char* Dataset_Dir( "C:/Data/" ); // Or take it from argv[1]
cv::Mat normal_matrix;
std::vector<cv::Mat>* image_stack;
for( int i=1; i<=endNumber; ++i )
{
    // Gives the entire stack of images for you to go through
    image_stack->push_back(cv::imread(std::format("%s/%03d-capture.png", Dataset, i), CV_LOAD_IMAGE_COLOR)); 

    normal_matrix = cv::imread(std::format("%s/%03d-capture.png", Dataset, i), CV_LOAD_IMAGE_COLOR);
}

Answer 3

我尝试过这段代码cv::VideoCapture cap("G:/var/cache/zoneminder/events/1/13/10/21/07/50/00/%3d-capture.jpg");，但它确实有效。但是，图像文件的文件名应该按顺序读取。

Answer 4

步骤：

将文件夹的路径存储在文本文件中 /home/user/Desktop/Test/train.txt
我的文本文件有条目：

/home/user/Desktop/Test/001.ak47/001_ /home/user/Desktop/Test/002.american-flag/002_ /home/user/Desktop/Test/007.bat/007_ /home/user/Desktop/Test/014.blimp/014_ /home/user/Desktop/Test/022.buddha-101/022 _
sprintf(path,"%s%04d.jpg",name,i);部分代码会附加文件名。我的文件格式001_0001.jpg适用于文件夹001.ak47，依此类推

代码从每个文件夹中读取20张图像并显示它。

 int main ()
    {
           ifstream file("/home/user/Desktop/Test/train.txt");
           string temp;
           string string2;
           int count = 0; // number of folders
               int number_of_folders = 5 ;
               char name[70];
           char path[70];
           while(count != number_of_folders)
           {
                getline(file, temp); // read first line of folder             //basically path to first folder
                int i=1;
                strcpy(name, temp.c_str());

                while(1)
              {

                sprintf(path,"%s%04d.jpg",name,i);
                Mat src= imread(path,1);

                 if(!src.data || src.rows == 0 ||  i == 21 ) break;        //use only 20 images for training
                imshow("src",src);
                i++;
                waitKey();

               }


                count = count+1 ;
                if(count == number_of_folders)
                    break;
           }
         file.close();
         return(0);
    }

如何在OpenCV中读取“.jpg”图像序列？

4 个答案: