如何从MySQL三个表中获取数据？

Question

我有三个表：产品名称，参数名称和某些产品的参数值：

产品

+-------+-------------+ 
|   id  |  name       |  
+-------+-------------+
|   1   |  A100       |
+-------+-------------+
|   2   |  B250       |
+-------+-------------+

PARAMS

+-------+-------------+ 
|   id  |  name       |  
+-------+-------------+
|   1   |  width      |
+-------+-------------+
|   2   |  color      |
+-------+-------------+

paramsofproducts

+-------+-----------+-----------+-----------+ 
|   id  |  product  |  param    |  value    |
+-------+-----------+-----------+-----------+ 
|   1   |     1     |    1      |   120     |
+-------+-----------+-----------+-----------+  
|   2   |     1     |    2      |  white    |
+-------+-----------+-----------+-----------+ 
|   3   |     2     |    1      |   275     |
+-------+-----------+-----------+-----------+  
|   4   |     2     |    2      |  black    |
+-------+-----------+-----------+-----------+

如何通过一个查询获取此表（所有产品+参数作为列）？我不能用JOIN来做。

+-------+----------+-----------+-----------+ 
|   id  |  name    |  width    |  color    |
+-------+----------+-----------+-----------+ 
|   1   |  A100    |   120     |  white    |
+-------+----------+-----------+-----------+ 
|   2   |  B250    |   275     |  black    |
+-------+----------+-----------+-----------+

Answer 1

我无法呈现您想要的结果，但结果中可能有一些JSON可能的解决方法：

SELECT products.id, products.name, CONCAT('[{',GROUP_CONCAT('"',REPLACE(params.name,  '"', '\\"'),'":"', REPLACE(paramsofproducts.value, '"', '\\"'),'"'),'}]') as params
FROM paramsofproducts 
LEFT JOIN products ON products.id = paramsofproducts.product 
LEFT JOIN params ON params.id = paramsofproducts.param
GROUP BY products.name

结果：

id | name | params
1  | A100 | [{"width":"120","color":"white"}]
2  | B250 | [{"width":"275","color":"black"}]

编辑：转义“