在lib中编写PHP代码:
$spellquery = doquery("SELECT id,name,type FROM {{table}}","habilidades");
$userspells = explode(",",$userrow["spells"]);
$userrow["magiclist"] = "";
while ($spellrow = mysql_fetch_array($spellquery)) {
$spell = false;
foreach($userspells as $a => $b) {
if ($b == $spellrow["id"]) { $spell = true; }
}
if ($spell == true) {
$userrow["magiclist"] .= "<a href=\"index.php?do=habilidad:".$spellrow["id"]."\"><img border=0 src=\"estilo/imagenes/skills/".$spellrow["name"].".png\" ></a><br />";
}
}
if ($userrow["magiclist"] == "") { $userrow["magiclist"] = "none"; }
模板页面中的代码:
<div>
{{magiclist}}
</div>
在页面中显示:http://lordehsa.5gbfree.com/estilo/imagenes/skills/out.JPG
我想要这样做:http://lordehsa.5gbfree.com/estilo/imagenes/skills/out2.jpg
答案 0 :(得分:0)
只需删除<br />
即可在一行中显示图片!