Google Apps脚本:解析XML会导致错误:“无法在对象中找到函数getChildren”

时间:2013-11-08 18:07:03

标签: javascript xml google-apps-script google-sheets

我正在尝试使用Google电子表格中的Google Apps脚本解析以下XML文档。特别是我想要解析lineItems的值及其属性coaCode的值,例如RTLR = 50211.000000:

<ReportFinancialStatements Major="1" Minor="0" Revision="1">
      <FinancialStatements>
      <COAMap></COAMap>
         <AnnualPeriods>
         <FiscalPeriod Type="Annual" EndDate="2009-06-30" FiscalYear="2009">
            <Statement Type="INC">
                <FPHeader>
                    <PeriodLength>12</PeriodLength>
                    <Source Date="2009-09-23">ARS</Source>
                </FPHeader>
                <lineItem coaCode="SREV">50211.000000</lineItem>
                <lineItem coaCode="RTLR">50211.000000</lineItem>
                <lineItem coaCode="SCOR">12001.000000</lineItem>
            </Statement>
        </FiscalPeriod>

这是我的代码段:

function parse(txt) {

  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheets()[0];

  var document = XmlService.parse(txt);
  var root = document.getRootElement();
  var elements = root.getChild('FinancialStatements').
         getChild('AnnualPeriods').getChildren('FiscalPeriod');  

  var columnOffset = 2;
  var rowOffset = 5;
  for (var i = 0; i < elements.length; i++) {
    var column = elements.length - i + columnOffset;
    var endDate = elements[i].getAttribute('EndDate').getValue();
    var fiscalYear = elements[i].getAttribute('FiscalYear').getValue();
    var fiscalPeriodType = elements[i].getAttribute('Type').getValue();

    // ***** SCRIPT CRASHES HERE: *****
    var values = elements[i].getChildren('Statement').getChildren('lineItem');

   for (var j = 0; j < values.length; j++) {
     var row = j + rowOffset;
     var value = values[j].getValue();
     sheet.getRange(row,column).setValue(value);
   }
  }
}

当我运行代码时,它会在

行崩溃

var values = elements[i].getChildren('Statement').getChildren('lineItem');

错误消息:

TypeError: Cannot find function getChildren in object [Element: <Statement/>],
   [Element: <Statement/>],[Element: <Statement/>].

我试图找到错误几个小时,但没有成功(我尝试了.getChildren组合的不同变体)。

您对我的代码可能出现的问题有什么想法吗?

2 个答案:

答案 0 :(得分:2)

对于这样的XML:

<ReportFinancialStatements Major="1" Minor="0" Revision="1">
  <FinancialStatements>
    <COAMap />
    <AnnualPeriods>
      <FiscalPeriod Type="Annual" EndDate="2009-06-30" FiscalYear="2009">
        <Statement Type="INC">
          <FPHeader>
            <PeriodLength>12</PeriodLength>
            <Source Date="2009-09-23">ARS</Source>
          </FPHeader>
          <lineItem coaCode="SREV">50211.000000</lineItem>
          <lineItem coaCode="RTLR">50211.000000</lineItem>
          <lineItem coaCode="SCOR">12001.000000</lineItem>
        </Statement>
      </FiscalPeriod>
    </AnnualPeriods>
  </FinancialStatements>
</ReportFinancialStatements>

变化:

...
//var values = elements[i].getChildren('Statement').getChildren('lineItem');
var values = elements[i].getChildren('Statement')[0].getChildren('lineItem');
...

答案 1 :(得分:0)

或者,您可以进行以下更改:

//var values = elements[i].getChildren('Statement').getChildren('lineItem');
 var values = elements[i].getChild('Statement').getChild('lineItem');

这个以及@wchiquito提到的代码更改将在数据存在于第一个&#34; Statement&#34;节点