这里我正在创建一个模拟猜谜游戏的简单练习Windows手机应用程序。我有一个运行游戏的while循环,直到用户猜出正确的答案;我想要做的是在每个循环的开始,等待用户通过在文本框中按Enter键来触发事件。我是这个想法的新手,没有多线程经验。 我正在接受未经授权的访问,我不确定是什么导致它。
public partial class MainPage : PhoneApplicationPage
{
Random r;
int guess;
static AutoResetEvent autoEvent;
// Constructor
public MainPage()
{
InitializeComponent();
r = new Random();
autoEvent = new AutoResetEvent(false);
Thread t = new Thread(PlayGuessGame);
t.Start();
}
private void PlayGuessGame()
{
bool hasWon = false;
int secretNumber = r.Next(1, 3);
int tries = 1;
messageTextBox.Text = "Guess a number";
while (!hasWon)
{
autoEvent.WaitOne();
if (guess == secretNumber) //if user wins
{
messageTextBox.Text = "Congratulations! You've guess the correct number! It took {0} tries.";
}
else
{
tries++;
if (guess < secretNumber)
messageTextBox.Text = "Guess higher!";
else
messageTextBox.Text = "Guess lower!";
lastGuessTextBox.Text = guess.ToString();
}
}
}
private void guessTextBox_KeyDown(object sender, KeyEventArgs e)
{
if (e.Key == Key.Enter)
{
guess = int.Parse(guessTextBox.Text);
autoEvent.Set();
}
}
}
答案 0 :(得分:3)
您遇到的问题是因为您尝试从未创建的线程访问对象。因此,运行PlayGuessGame()的线程不应该在该沙箱中播放。你可以通过使用MethodInvoder来解决这个问题:
private void PlayGuessGame()
{
bool hasWon = false;
int secretNumber = r.Next(1, 3);
int tries = 1;
messageTextBox.Text = "Guess a number";
while (!hasWon)
{
autoEvent.WaitOne();
if (guess == secretNumber) //if user wins
{
this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Congratulations! You've guess the correct number! It took {0} tries."; }));
}
else
{
tries++;
if (guess < secretNumber)
this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Guess higher!"; }));
else
this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Guess lower!"; }));
this.Invoke(new MethodInvoker(delegate { lastGuessTextBox.Text = guess.ToString(); }));
}
}
}
我肯定会推荐Brian Warshaw的评论,这应该是一个事件驱动的GUI。希望这有帮助,你可以在其他地方使用你使用线程!