从SQL 2008查询中提取的重复记录

Question

我有以下表格 -

**TimeLogs**
ID
UserID
JobID
TimeTaken

**Jobs**
ID
EstimatedTime
ActualTime

**ClockInLogs**
ID
UserID
ClockDateTimeIn
ClockDateTimeOut

以下查询生成重复记录 -

SELECT tl.JobID, TimeTaken as 'HoursSold',
DATEDIFF(minute, ClockDateTimeIn, ClockDateTimeOut) / 60 as Hours_Difference,
DATEDIFF(second, ClockDateTimeIn, ClockDateTimeOut) / 60 as Minutes_Difference
from TimeLogs tl
INNER JOIN Jobs j on tl.JobID = j.ID
LEFT JOIN ClockInLogs cil on tl.UserID = cil.UserID
where tl.UserID = 10000 and 
    ClockDateTimeIn BETWEEN DATEADD(wk, DATEDIFF(wk,0,'11/08/2013'), 0) AND 
    DATEADD(wk, DATEDIFF(wk,0,'11/08/2013'), 6)
    group by tl.ID, tl.JobID, j.TotalEstimatedCharge, tl.TimeTaken, cil.ClockDateTimeIn, cil.ClockDateTimeOut

我希望它做的是返回HoursWorked，Hours_Difference和Minutes_Difference之和 - 没有重复。我无法解决重复的来源。有什么想法吗？

由于

Answer 1

您需要将小时和分钟相加而不是按小组进行分组：

你这样做可能会超过60分钟。

select
    tl.JobID, 
    TimeTaken as 'HoursSold',
    Sum(datediff(n, ClockDateTimeIn, ClockDateTimeOut) / 60) Hours_Difference,
    Sum(datediff(s, ClockDateTimeIn, ClockDateTimeOut) / 60) Minutes_Difference
from 
    TimeLogs tl
        inner join
    Jobs j 
        on tl.JobID = j.ID
        left join
    ClockInLogs cil 
        on tl.UserID = cil.UserID
where 
    tl.UserID = 10000 and 
    ClockDateTimeIn between dateadd(wk, datediff(wk,0,'11/08/2013'), 0) and
    dateadd(wk, datediff(wk,0,'11/08/2013'), 6)
group by 
    tl.JobID, 
    tl.TimeTaken

Answer 2

在没有看到数据的情况下很难确定，但我怀疑你是按照应该求和的字段进行分组（TimeTaken，ClockDateTimeIn和ClockDateTimeOut）：

SELECT tl.JobID,
SUM(TimeTaken) as 'HoursSold',
SUM(DATEDIFF(minute, ClockDateTimeIn, ClockDateTimeOut) / 60) as Hours_Difference,
SUM(DATEDIFF(second, ClockDateTimeIn, ClockDateTimeOut) / 60) as Minutes_Difference
from TimeLogs tl
INNER JOIN Jobs j on tl.JobID = j.ID
LEFT JOIN ClockInLogs cil on tl.UserID = cil.UserID
where tl.UserID = 10000 and 
    ClockDateTimeIn BETWEEN DATEADD(wk, DATEDIFF(wk,0,'11/08/2013'), 0) AND 
    DATEADD(wk, DATEDIFF(wk,0,'11/08/2013'), 6)
group by tl.JobID

请注意，我还删除了不在select中的字段的group by，因为这也会创建重复的外观。