Question

我试图运行for循环，它会替换作为列表传递的文件中的字符串。

示例：

Filename1

Filename2

File name3

File name4

我目前的代码是：

for i in `grep -Rl 'OLD' *`; do                                                                                                                 
> perl -pe 's/OLD/NEW/g' -pi "$i"
> done

Can't open File: No such file or directory.
Can't open name3: No such file or directory.
Can't open File: No such file or directory.
Can't open name3: No such file or directory.
Can't open File: No such file or directory.
Can't open name4: No such file or directory.

谢谢！

Answer 1

为了避免分词，你可以说：

grep -Rl 'OLD' * | while read i; do
  perl -pe 's/OLD/NEW/g' -pi "$i";
done

或

while read i; do
  perl -pe 's/OLD/NEW/g' -pi "$i";
done < <(grep -Rl 'OLD' *)

Answer 2

尝试将xargs与sed

一起使用

grep -Rl 'OLD' * -Z | xargs -0 sed -i 's/OLD/NEW/g'

请注意使用-Z grep选项来终止 null 的输出，与xargs -0兼容。这将克服文件名中的空白问题。

Answer 3

你也可以使用find来做到这一点：

find -name 'File*' -exec sed -i 's,OLD,NEW,g' {} \;

while循环列表中的空格

3 个答案: