Question

嗨Iam Fresher in Jmeter

我编写了一个Java Sampler代码（Copy＆amp; Paste），运行此代码后获取成功消息但是请求和响应数据没有显示..如何获取请求和响应数据，我也想传递一些参数，是否有可能

我的Jsampler代码是

package com.wordpress.newspaint.jmeter.java.demo;

import java.io.Serializable;
import org.apache.jmeter.protocol.java.sampler.AbstractJavaSamplerClient;
import org.apache.jmeter.config.Arguments;
import org.apache.jmeter.samplers.SampleResult;
import org.apache.jmeter.protocol.java.sampler.JavaSamplerContext;

public class ExampleJavaTestClassRR extends AbstractJavaSamplerClient implements Serializable {
    private static final long serialVersionUID = 1L;

    // set up default arguments for the JMeter GUI
    @Override
    public Arguments getDefaultParameters() {
        Arguments defaultParameters = new Arguments();
        defaultParameters.addArgument("URL", "http://www.google.com/");
        defaultParameters.addArgument("SEARCHFOR", "newspaint");
      //  defaultParameters.addArgument("ENTITY","BANK");
        return defaultParameters;
    }

    public SampleResult runTest(JavaSamplerContext context) {       
        String urlString = context.getParameter( "URL" );
        String searchFor = context.getParameter( "SEARCHFOR" );
      //  String ENTITY = context.getParameter( "ENTITY" );

        SampleResult result = new SampleResult();
        result.sampleStart(); // start stopwatch

        try {
            java.net.URL url = new java.net.URL(urlString + "?q=" + searchFor);
            java.net.HttpURLConnection connection = (java.net.HttpURLConnection)url.openConnection(); // have to cast connection
            connection.setRequestMethod("POST");
            connection.connect();
            result.setSuccessful( true );
            result.setResponseMessage("URL IS"+ url);
            result.setResponseMessage( "Successfully performed actionSSSSn" );
            result.setResponseCodeOK(); // 200 code
        } catch (Exception e) {
           // result.sampleEnd(); // stop stopwatch
            result.setSuccessful( false );
            result.setResponseMessage( "Exception: " + e );

            // get stack trace as a String to return as document data
            java.io.StringWriter stringWriter = new java.io.StringWriter();
            e.printStackTrace( new java.io.PrintWriter( stringWriter ) );
            result.setResponseData( stringWriter.toString() );
            result.setDataType( org.apache.jmeter.samplers.SampleResult.TEXT );
            result.setResponseCode( "500" );
        }
        result.sampleEnd();
        return result;
    }
    void teardownTest() {
        System.out.println("inside tear Down:");
    }
}

Answer 1

<强>第一：

您的代码示例不是很正确。

这一行：

result.setResponseData( stringWriter.toString() );

根据JavaDoc，它已被弃用

/**
 * Sets the responseData attribute of the SampleResult object.
 * Should only be called after setting the dataEncoding (if necessary)
 *
 * @param response
 *            the new responseData value (String)
 *
 * @deprecated - only intended for use from BeanShell code
 */

因此，如果您想以这种方式设置响应数据，则需要使用ie __Beanshell函数

调用setResponseData的正确方法是

result.setDataEncoding("UTF-8");
result.setResponseData("Everything is fine".getBytes());

或

result.setResponseData("Everything is fine", "UTF-8);

<强>第二

您的代码假设结果仅在失败的情况下返回。将默认http://www.google.com/ URL更改为某个不存在的URL，您将获得异常堆栈跟踪作为响应。

如果您需要在成功时返回某些内容，则需要在try块的末尾添加上面的任何行。

<强>第三

据我所知，您无法为Java Request设置请求数据。您需要开发一个能够设置它的采样器。我建议查看ExampleSampler的来源

/src/examples/org/apache/jmeter/examples/sampler/ExampleSampler.java

以及现有的JavaTest和SleepTest Java Request采样器：

/src/protocol/java/org/apache/jmeter/protocol/java/test/JavaTest.java
/src/protocol/java/org/apache/jmeter/protocol/java/test/SleepTest.java

所有三个都包含答案“我也想传递一些参数，是否可能”片

来源可从JMeter download page

获取

如何获得请求和响应数据结果

1 个答案: