Question

我想基于URL在视图中显示图像，但是url作为推送通知，我正在获得所有PNS，也成功获得图像URL但图像显示不正确。下面的代码，我正在使用当我得到新的推送通知我打开通知和调用方法whch是在另一个视图，我想设置图像。

- (void)application:(UIApplication *)application
didReceiveRemoteNotification:(NSDictionary *)userInfo {
if (application.applicationState == UIApplicationStateActive) 
{
    UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Did receive a Remote Notification" message:[NSString stringWithFormat:@"You Have a Notification :\n%@",userInfo[@"aps"][@"alert"]]delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];

    [alertView show];
}
NSLog(@"Payload: %@", userInfo);
imageURL =  userInfo[@"aps"][@"alert"];
MainViewController *mv =  [[MainViewController alloc] init];
    [mv  sshowansimage:imageURL]; // CALL METHOD OF ANTOHER CLASS WHERE I WANT TO SET IMAGE

}

现在这里是sshowansimage方法的代码，它是mainviewcontrriler类

-(void) sshowansimage:(NSString *) strImageURL{


NSURL *imageURL = [NSURL URLWithString:strImageURL];

dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_BACKGROUND, 0), ^{
    NSData *imageData = [NSData dataWithContentsOfURL:imageURL];

    dispatch_async(dispatch_get_main_queue(), ^{
        // Update the UI
        imgeview.image = [UIImage imageWithData:imageData];
    });
});
}

Answer 1

试试这个

-(void) sshowansimage:(NSString *) strImageURL{

NSURL *imageURL = [NSURL URLWithString:strImageURL];

dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_BACKGROUND, 0), ^{
    NSData *imageData = [NSData dataWithContentsOfURL:imageURL];
    [self performSelectorOnMainThread:@selector(showImage:) withObject:imageData waitUntilDone:YES];
});

}

-(void)showImage:(NSData*)imageAsData
{
imgeview.image = [UIImage imageWithData:imageAsData];
}

始终在主线程中执行与UI相关的任务

如何在来自推送通知的URL中显示图像视图中的图像

1 个答案: