Question

我在phpMyAdmin中使用MySQL，我有一个表，我试图得到以下结果，如下图所示：

我有一个表格结构如下;

+---------+-----------+-------+--------+---------+----------+
| EntryID | RegDate   |  Code | Buying | Selling | Averages |
+---------+-----------+-------+--------+---------+----------+
| 1       |2013-11-08 |  USD  | NULL   | NULL    | 0.814    |
+---------+-----------+-------+--------+---------+----------+   
| 2       |2013-11-08 |  GBP  | NULL   | NULL    | 0.114    |
+---------+-----------+-------+--------+---------+----------+

将主键作为EntryID，我试图获得如下所示的输出;

+-----------+-------+-------+
| RegDate   |  USD  |  GBP  |
+-----------+-------+-------+
|2013-11-08 | 0.814 | 0.114 |
+---------+---------+-------+

Answer 1

SELECT RegDate,
       SUM(CASE WHEN Code='USD' THEN Averages ELSE 0 END) as USD,
       SUM(CASE WHEN Code='GBP' THEN Averages ELSE 0 END) as GBP
FROM T
GROUP BY RegDate

SQLFiddle demo

Answer 2

SELECT USD.RegDate, USD.Averages as USD,
GBP.Averages as GBP From
(SELECT RegDate, Averages
From Table1 where Code = 'USD') USD
Inner join
(SELECT RegDate, Averages
From Table1 where Code = 'GBP') GBP
ON USD.RegDate = GBP.RegDate

<强> Sample Fiddle

Answer 3

你可以简单地JOIN表格，为你需要的每种货币使用一次表格;

SELECT usd.RegDate, usd.averages USD, gbp.averages GBP
FROM Table1 usd
JOIN Table1 gbp
  ON usd.regdate = gbp.regdate
 AND usd.code = 'USD'
 AND gbp.code = 'GBP';

An SQLfiddle to test with

请注意，此查询假设每个货币每个日期只存在一次以产生良好的结果，如果不是这种情况，则应将其添加到样本数据中。

Answer 4

尝试：

SELECT EntryID, regDate,
SUM(CASE Code WHEN 'USD' THEN Averages ELSE 0 END) as USD,
SUM(CASE Code WHEN 'GBP' THEN Averages ELSE 0 END) as GBP
FROM TableA
GROUP BY regDate

请参阅Demo

如何从一个表mysql中组合两个不同查询的结果

4 个答案: