Question

我试图弄清楚如何从SQL Server过滤数据集。

DECLARE @OUTPUT AS TABLE (FILTER INT,PART INT,LOT INT)
INSERT INTO @OUTPUT (FILTER,PART,LOT) VALUES
(1,1377882157,1379436702),
(1,1377882157,1382038239),
(1,1377882157,1382038531),
(3,1373463498,1380792160),
(3,1377882157,1379436702),
(4,1373638746,1382475541),
(4,1377882157,1379436702),
(5,1373463498,1380792160),
(5,1373463959,1380792272),
(5,1373464034,1380791899),
(5,1373638746,1379326622),
(5,1373638746,1382475541),
(5,1373638756,1383222295),
(5,1377882157,1379436702),
(5,1377882157,1382038239),
(5,1377882157,1382038531),
(5,1377882159,1383658054),
(8,1373638746,1379326622),
(8,1377882157,1379436702)

我正在寻找PART＆amp; LOT存在于每个过滤器组中。过滤器组是根据用户选择动态生成的。

提供的数据只返回1个项目（例如1377882157,1379436702），因为它是所有过滤器组中唯一存在的项目。

这就是我现在所拥有的......想知道是否有更好的方法可以做到这一点？

DECLARE @FILTER_CNT INT
SET @FILTER_CNT = 5

SELECT
    F_PART,
    F_LOT
FROM @FILTERED_LOTS
GROUP BY F_PART,F_LOT
HAVING COUNT(FILTER) = @FILTER_CNT

我不需要定义FILTER_CNT的方法正是我的想法。

Answer 1

您可以使用子查询替换@FILTER_CNT

SELECT PART, LOT
  FROM output
 GROUP BY PART, LOT
HAVING COUNT(FILTER) = 
(
  SELECT COUNT(DISTINCT FILTER) 
    FROM output
)

输出：

|       PART |        LOT |
|------------|------------|
| 1377882157 | 1379436702 |

这是 SQLFiddle 演示

Answer 2

--DECLARE @FILTER_CNT INT --SET @FILTER_CNT = 5

use this instead

SELECT
    PART,
    LOT,count(FILTER) as FILTER_total_count
FROM @OUTPUT
GROUP BY PART,LOT
HAVING COUNT(FILTER)=(select count(distinct FILTER) from @OUTPUT)

有没有更好的方法来过滤每个组中存在的数据？

2 个答案: