Question

我正在计算几千点的2D delaunay三角剖分。每个点都有超过x和y坐标的更多数据。因此，我想知道是否有可能检索每个点的索引，以便我可以在另一个向量中访问我自己的点结构。

目前，当我从Face_handle访问顶点时，它返回一个点（即x，y坐标）如何通过其ID（索引）而不是其x，y坐标返回每个顶点？谢谢。

#include <vector>
#include <CGAL/Exact_predicates_inexact_constructions_kernel.h>
#include <CGAL/Delaunay_triangulation_2.h>

typedef CGAL::Exact_predicates_inexact_constructions_kernel Kernel;
typedef CGAL::Delaunay_triangulation_2<Kernel> Delaunay;
typedef Kernel::Point_2 Point;

void example() {

  std::vector<Point> points;
  points.push_back(Point(1,1)); //index 0
  points.push_back(Point(1,2)); //index 1
  points.push_back(Point(1,3)); //index 2
  points.push_back(Point(2,1)); //index 3
  points.push_back(Point(2,2)); //index 4
  points.push_back(Point(2,3)); //index 5

  Delaunay triangulation;
  triangulation.insert(points.begin(),points.end());

  for(Delaunay::Finite_faces_iterator fit = triangulation.finite_faces_begin();
      fit != triangulation.finite_faces_end(); ++fit) {

    Delaunay::Face_handle face = fit;
    std::cout << "Triangle:\t" << triangulation.triangle(face) << std::endl;
    std::cout << "Vertex 0:\t" << triangulation.triangle(face)[0] << std::endl;
  }
}

输出（x，y坐标）：

Triangle:   1 3 1 2 2 2
Vertex 0:   1 3
Triangle:   1 2 1 1 2 1
Vertex 0:   1 2
Triangle:   1 3 2 2 2 3
Vertex 0:   1 3
Triangle:   1 2 2 1 2 2
Vertex 0:   1 2

期望输出（指数）：

Triangle:   2   1   4
Vertex 0:   2
Triangle:   1   0   3
Vertex 0:   1 
Triangle:   2   4   5
Vertex 0:   2
Triangle:   1   3   4
Vertex 0:   1

Answer 1

您可以将任何信息附加到三角测量中的顶点。例如，要添加索引（unsigned int），您可以执行以下操作：

#include <CGAL/Exact_predicates_inexact_constructions_kernel.h>
#include <CGAL/Delaunay_triangulation_2.h>
#include <CGAL/Triangulation_vertex_base_with_info_2.h>
#include <vector>

typedef CGAL::Exact_predicates_inexact_constructions_kernel            Kernel;
typedef CGAL::Triangulation_vertex_base_with_info_2<unsigned int, Kernel> Vb;
typedef CGAL::Triangulation_data_structure_2<Vb>                       Tds;
typedef CGAL::Delaunay_triangulation_2<Kernel, Tds>                    Delaunay;
typedef Kernel::Point_2                                                Point;

int main() {

  std::vector< std::pair<Point,unsigned> > points;
  points.push_back( std::make_pair( Point(1,1), 0 ) );
  points.push_back( std::make_pair( Point(1,2), 1 ) );
  points.push_back( std::make_pair( Point(1,3), 2 ) );
  points.push_back( std::make_pair( Point(2,1), 3 ) );
  points.push_back( std::make_pair( Point(2,2), 4 ) );
  points.push_back( std::make_pair( Point(2,3), 5 ) );

  Delaunay triangulation;
  triangulation.insert(points.begin(),points.end());

  for(Delaunay::Finite_faces_iterator fit = triangulation.finite_faces_begin();
      fit != triangulation.finite_faces_end(); ++fit) {

    Delaunay::Face_handle face = fit;
    std::cout << "Triangle:\t" << triangulation.triangle(face) << std::endl;
    std::cout << "Vertex 0:\t" << triangulation.triangle(face)[0] << std::endl;
    std::cout << "Vertex 0:\t" << face->vertex(0)->info() << std::endl;
  }
}

CGAL - 在Delaunay三角剖分后检索顶点索引

1 个答案: