我遇到的情况是我需要向服务器发出多个请求,后续请求将取决于之前的请求
1) request 1
2) process data
3) request 2 based on data in step 2
4) process data
AFNetworking 2的最佳解决方法是什么
答案 0 :(得分:1)
在第一个请求的完成处理程序中调用第二个请求。以下是一些示例代码:
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager GET:@"http://example.com/resources.json" parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON Response 1: %@", responseObject);
// Process data here, and use it to set parameters or change the url for request2 below
[manager GET:@"http://example.com/request2.json" parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON Response 2: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error 2: %@", error);
}];
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error 1: %@", error);
}];
答案 1 :(得分:0)
我有一个游戏,最终实现了我自己的完成块和失败块,因此它们可以作为请求操作在某个线程上执行,方法是在AFHTTPRequestOperation类中添加一个类别
- (void)startAndWaitWithSuccess:(void (^)(AFHTTPRequestOperation *operation, id responseObject))success
failure:(void (^)(AFHTTPRequestOperation *operation, NSError *error))failure
{
[self start];
[super waitUntilFinished];
id responseObject = self.responseObject; // need this line for AFNetworking to create error;
if (self.error) {
if (failure) failure(self, self.error);
} else {
if (success) success(self, responseObject);
}
}
操作将开始,然后阻止线程直到操作完成。然后依靠成功或失败,在完成操作之前调用相应的块。
这样我可以一个接一个地链接多个请求操作,并且完成块将具有来自先前请求完成块的已处理数据