Question

当我把它放在我的网址"http:// localhost:8080 /ChickenTest/index.jsp"时，浏览器会显示此消息“请求的资源（/ChickenTest/index.jsp）不可用。”和eclipse控制台此消息“在DispatcherServlet中找不到具有URI [/ ChickenTest / index]的HTTP请求的映射，其名称为”dispatcherServlet“”

控制器：

package controller;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

import service.EggService;

@Controller
public class GeneralController {

    @Autowired
    EggService eggService;

    //jsp loaders
    @RequestMapping(value="/index")
    ModelAndView index(){
        ModelAndView mav = new ModelAndView();

        return mav;
    }

    //jsp loaders
    @RequestMapping(value="/Egg/indexEgg")
    ModelAndView indexEgg(){
        ModelAndView mav = new ModelAndView();

        return mav;
    }

    @RequestMapping(value="/Chicken/indexChicken")
    ModelAndView indexChicken(){
        ModelAndView mav = new ModelAndView();

        return mav;
    }

    @RequestMapping(value="/Farm/indexFarm")
    ModelAndView indexFarm(){
        ModelAndView mav = new ModelAndView();

        return mav;
    }
}

MVC-config.xml中：

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <!-- Uncomment and your base-package here:
         <context:component-scan
            base-package="org.springframework.samples.web"/>  -->


    <mvc:annotation-driven />

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
            <!-- Example: a logical view name of 'showMessage' is mapped to '/WEB-INF/jsp/showMessage.jsp' -->
            <property name="prefix" value="/WEB-INF/view/"/>
            <property name="suffix" value=".jsp"/>
    </bean>

</beans>

的web.xml：

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xmlns="http://java.sun.com/xml/ns/javaee"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
         id="WebApp_ID" version="2.5">

    <display-name>ChickenTest</display-name>

   <!--
        - Location of the XML file that defines the root application context.
        - Applied by ContextLoaderListener.
    -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:spring/application-config.xml</param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>


    <!--
        - Servlet that dispatches request to registered handlers (Controller implementations).
    -->
    <servlet>
        <servlet-name>dispatcherServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/mvc-config.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>dispatcherServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

Answer 1

在mvc-config.xml中，取消注释代码：

<!-- Uncomment and your base-package here:
         <context:component-scan
            base-package="org.springframework.samples.web"/>  -->

添加你的基础包，我认为它的控制器或其他东西。我认为这是个问题。

Answer 2

您正在使用路径 ChickenTest 访问该网址，但您已将其映射到您的控制器中鸡 @RequestMapping(value="/Chicken/indexChicken")

将RequestMapping替换为 ChickenTest ，或使用鸡访问该网址。

在DispatcherServlet中找不到具有URI [/ ChickenTest / index]的HTTP请求的映射，名称为“dispatcherServlet”

2 个答案: